绘制弹出菜单项的值为不可用，多谢！

绘制弹出菜单项的值为不可用，请教高手，谢谢！！！

VB.NET code

Dim ContextMenunew As ContextMenu = New ContextMenuContextMenunew.MenuItems.Clear()Dim myMenuItem1 As New MenuItem()Dim myMenuItem2 As New MenuItem()myMenuItem1 = New MenuItem()myMenuItem1.Text = "添加"ContextMenunew.MenuItems.Add(myMenuItem1)AddHandler (myMenuItem1.Click), AddressOf MenuClickmyMenuItem2 = New MenuItem()myMenuItem2.Text = "删除"ContextMenunew.MenuItems.Add(myMenuItem2)AddHandler (myMenuItem2.Click), AddressOf MenuClick

我想添加后的 删除 为不可用，请高手们教教我，谢谢！！！

[解决办法]
myMenuItem2.Enabled = false ???
[解决办法]
myMenuItem2 = New MenuItem()
myMenuItem2.Text = "删除"
myMenuItem2.Enabled = false
ContextMenunew.MenuItems.Add(myMenuItem2)
[解决办法]
myMenuItem2 .Enabled = false;

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