使用grep找到某个文件及其相邻行 我有个文件列表按时间排列。别如 ls -lrt 现在想用grep找到名字为 file1的那行，并且显示其上下相邻的行。请问该怎么写？ 最好能写成一句， 比如 ls -lrt | grep ....
[解决办法]
ls -lrt [解决办法] grep -C 1 "file1"
-A NUM, --after-context=NUM Print NUM lines of trailing context after matching lines. Places a line containing -- between contiguous groups of matches.
-B NUM, --before-context=NUM Print NUM lines of leading context before matching lines. Places a line containing -- between contiguous groups of matches.
-C NUM, --context=NUM Print NUM lines of output context. Places a line containing -- between contiguous groups of matches. [解决办法] grep 的 -A -B和-C参数就可以了
% grep -A <n> 'keyword' file # 匹配 keyword 的下 n 行 % grep -B <n> 'keyword' file # 匹配 keyword 的上 n 行 % grep -C <n> 'keyword' file # 匹配 keyword 的上 n 行及下 n 行
