算法生成一-9，a-b的随机十位数

算法生成1-9，a-b的随机十位数

譬如你行随机生成小于等于10位的数字?? 1sd3sd34t5??? 3g3t44h

算法如下

public class test {public static String[] z = {"0","1","2","3","4","a","b","c","d",""};/** * @param args */public static void main(String[] args) {// TODO Auto-generated method stubgetAInt(10,"");}public static String getAInt(int index,String result){for(int i=0;i<z.length;i++){if(index==1){System.out.println(result+z[i]);continue;}System.out.println("开始进入递归");getAInt(index-1,result+z[i]);System.out.println("结束递归");}return "";}}