求个算法！！亲
List<<List<T>>如何行专列
如上图，Excel按行读取，读出来的数据是
按行读取,List<string> 并且添加到List<List<string>>中。
类似于这个操作
var lst0 = new List<string> { "HJ00RY001-CB04", "6903148048801", "6920177916161", "6924882335385", "6924882335514" };
var lst1 = new List<string> { "", "HJ00RY001-CB04-HW01", "HJ00RY001-CB04-HW02", "HJ00RY001-CB04-HW03", "HJ00RY001-CB04-HW04" };
var lst2 = new List<string> { "", "30", "30", "30", "30" };
var lst3 = new List<string> { "", "30", "30", "30", "30" };
var lst4 = new List<string> { "", "40", "40", "40", "40" };
var lst5 = new List<string> { "", "48000", "48000", "48000", "48000" };
var lst6 = new List<string> { "", "4", "4", "4", "4" };
var lstData = new List<List<string>> {lst0, lst1, lst2, lst3, lst4, lst5, lst6};
List[0]{"HJ00RY001-CB04","","","","","",""}
List[1]{"6903148048801","HJ00RY001-CB04-HW01","30","30","40","48000","4"}
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Text.RegularExpressions;
using System.Threading.Tasks;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
var lst0 = new List<string> { "HJ00RY001-CB04", "6903148048801", "6920177916161", "6924882335385", "6924882335514" };
var lst1 = new List<string> { "", "HJ00RY001-CB04-HW01", "HJ00RY001-CB04-HW02", "HJ00RY001-CB04-HW03", "HJ00RY001-CB04-HW04" };
var lst2 = new List<string> { "", "30", "30", "30", "30" };
var lst3 = new List<string> { "", "30", "30", "30", "30" };
var lst4 = new List<string> { "", "40", "40", "40", "40" };
var lst5 = new List<string> { "", "48000", "48000", "48000", "48000" };
var lst6 = new List<string> { "", "4", "4", "4", "4" };
var lstData = new List<List<string>> { lst0, lst1, lst2, lst3, lst4, lst5, lst6 };
var result = R2C(lstData);
foreach (var item in result)
{
Console.WriteLine(string.Join(", ", item.Select(x => """ + x + """).ToArray()));
}
}
static List<List<string>> R2C(List<List<string>> source)
{
return Enumerable.Range(0, source[0].Count).Select(x =>
Enumerable.Range(0, source.Count).Select(y => source[y][x]).ToList()).ToList();
}
}
}
