unix、linux下只输出本机mac地址的命令
unix、linux下只输出本机mac地址的shell命令？
不要ifconfig那种的输出一大堆。。。最好时只输出mac字符串
[解决办法]
# ifconfig
[解决办法]
grep HWaddr
[解决办法]
awk '{print $4,$5}'
HWaddr 00:50:56:8E:00:3B
HWaddr 52:54:00:B8:7D:FA
#
[解决办法]
ifconfig
[解决办法]
awk '{print $5}'
[解决办法]
head -1
[解决办法]
我想已经猜到楼主意欲何为了。。。
楼主还是直接用ioctl吧
#include <stdio.h>
#include <string.h>
#include <unistd.h>
#include <sys/ioctl.h>
#include <sys/types.h>
#include <sys/socket.h>
#include <netinet/in.h>
#include <arpa/inet.h>
#include <net/if.h>
int getmac(char *ethname, char *macbuf)
{
int sock;
struct ifreq iface;
char tmp_mac[10];
sock = socket(PF_INET, SOCK_DGRAM, 0);
strcpy(iface.ifr_name, ethname);
if(ioctl(sock, SIOCGIFHWADDR, &iface) != 0) {
close(sock);
return 1;
}
memcpy(tmp_mac, iface.ifr_hwaddr.sa_data, 6);
sprintf(macbuf, "%02X:%02X:%02X:%02X:%02X:%02X",
tmp_mac[0] & 0xFF, tmp_mac[1] & 0xFF, tmp_mac[2] &0xFF,
tmp_mac[3] & 0xFF, tmp_mac[4] & 0xFF, tmp_mac[5] & 0xFF);
return 0;
}
int main(void)
{
char buf[256];
getmac("eth0", buf);
puts(buf);
return 0;
}
