新手C++求助,此程序有点错误求,高手帮忙改下或者帮忙写个，小弟在这感激不尽啊...
题目要求:
用c++建立一个二维坐标系的类TwoCoor，用x、y表示坐标值，实现两坐标点的加、减运算，计算两坐标点间的距离，并重载输入/输出运算符，使之能够直接输入/输出坐标点的坐标值.
运行环境VC6.0或CodeBlocks
下面是我在网上找的代码,有几个错误,但不会修改.......
#include<iostream>
#include<cmath>
using namespace std;
class TwoCoor
{
private:
double x,y;
public:
TwoCoor(double X=0,double Y=0):x(X),y(Y) {};
friend TwoCoor operator+(TwoCoor p1,TwoCoor p2);
friend TwoCoor operator-(TwoCoor p1,TwoCoor p2);
friend double dist(TwoCoor p1,TwoCoor p2);
friend TwoCoor &operator<<(ostream &os,TwoCoor &t);
friend TwoCoor &operator>>(istream &is,TwoCoor &t);
};
TwoCoor operator+(TwoCoor p1,TwoCoor p2)
{
return TwoCoor(p1.x+p2.x,p1.y+p2.y);
}
TwoCoor operator-(TwoCoor p1,TwoCoor p2)
{
return TwoCoor(p1.x-p2.x,p1.y-p2.y);
}
double dist(TwoCoor p1,TwoCoor p2)
{
double x=(p1.x-p2.x);
double y=(p1.y-p1.y);
return sqrt(x*x+y*y);
}
TwoCoor &operator<<(ostream &os,TwoCoor &t)
{
os<<"\t"<<t.x<<"\t";
os<<t.y<<endl;
return t;
}
TwoCoor &operator>>(istream &is,TwoCoor &t)
{
cout<<"坐标点的横坐标:";
is>>t.x;
cout<<"坐标点的纵坐标:";
is>>t.y;
return t;
}
int main()
{
TwoCoor t1,t2;
char select;
while(1)
{
cout<<"------------------坐标点计算系统-----------------------"<<endl;
cout<<" 0 计算两坐标点对应坐标之和 "<<endl;
cout<<" 1 计算两坐标点对应坐标之差 "<<endl;
cout<<" 2 计算两坐标点的距离 "<<endl;
cout<<" 3 退出系统 "<<endl;
cout<<"*******************************************************"<<endl;
cout<<"请输入你的选择:";
cin>>select;
if(select=='0')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"\t"<<"\t"<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"两坐标点的对应坐标相加为:"<<operator+(t1,t2);
}
else if(select=='1')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"\t"<<"\t"<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"两坐标点的对应坐标相减为:"<<operator-(t1,t2);
}
else if(select=='2')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"两坐标点的距离为:"<<dist(t1,t2)<<endl;
}
else if(select=='3')
exit(0);
else
{
cout<<"输入错误，请重新输入"<<endl;
continue;
}
}
}
friend ostream &operator<<(ostream &os,TwoCoor &t);
friend istream &operator>>(istream &is,TwoCoor &t);
};
TwoCoor operator+(TwoCoor p1,TwoCoor p2)
{
TwoCoor t;
t.x = p1.x+p2.x;
t.y = p1.y+p2.y;
return t;
}
TwoCoor operator-(TwoCoor p1,TwoCoor p2)
{
TwoCoor t;
t.x = p1.x-p2.x;
t.y = p1.y-p2.y;
return t;
}
double dist(TwoCoor p1,TwoCoor p2)
{
double x=(p1.x-p2.x);
double y=(p1.y-p1.y);
return sqrt(x*x+y*y);
}
ostream &operator<<(ostream &os,TwoCoor &t)
{
os<<"\t"<<t.x<<"\t";
os<<t.y<<endl;
return os;
}
istream &operator>>(istream &is,TwoCoor &t)
{
cout<<"坐标点的横坐标:";
is>>t.x;
cout<<"坐标点的纵坐标:";
is>>t.y;
return is;
}
int main()
{
TwoCoor t1,t2;
char select;
while(1)
{
cout<<"------------------坐标点计算系统-----------------------"<<endl;
cout<<" 0 计算两坐标点对应坐标之和 "<<endl;
cout<<" 1 计算两坐标点对应坐标之差 "<<endl;
cout<<" 2 计算两坐标点的距离 "<<endl;
cout<<" 3 退出系统 "<<endl;
cout<<"*******************************************************"<<endl;
cout<<"请输入你的选择:";
cin>>select;
if(select=='0')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"\t"<<"\t"<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"两坐标点的对应坐标相加为:";
TwoCoor t3 =t1+t2;
cout<< t3;
}
else if(select=='1')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"\t"<<"\t"<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"两坐标点的对应坐标相减为:";
TwoCoor t4 = t1-t2;
cout<< t4;
}
else if(select=='2')
{
cout<<"请输入坐标点1的坐标:"<<endl;
cin>>t1;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点1";
cout<<t1;
cout<<"---------------------------------------"<<endl;
cout<<"请输入坐标点2的坐标:"<<endl;
cin>>t2;
cout<<"---------------------------------------"<<endl;
cout<<"\t"<<"横坐标"<<"\t"<<"纵坐标"<<endl;
cout<<"点2";
cout<<t2;
cout<<"---------------------------------------"<<endl;
cout<<"两坐标点的距离为:";
double distance = dist(t1,t2);
cout<< distance;
}
else if(select=='3')
exit(0);
else
{
cout<<"输入错误，请重新输入"<<endl;
continue;
}
}
}
[解决办法]
其它地方没什么错误，就是在
cout<<"两坐标点的对应坐标相加为:"<<operator+(t1,t2);
cout<<"两坐标点的对应坐标相减为:"<<operator-(t1,t2);
cout<<"两坐标点的距离为:"<<dist(t1,t2)<<endl;
这三个地方出了错，可能是是重载<<之后,编译器不知道到底是先调用operator+（t1,t2),还是cout<<t;
造成了混乱，所以编写的时候，适当的将这两个过程分开，肯能会更好一点。我的理解是这样。
[解决办法]
VS2010下编译通过。运行正常。
VC6.0可能本身有BUG，可以这样修改：
#include<iostream.h> //改为.h
#include<cmath>
//using namespace std;//std就不需要了
#include <process.h> //exit()的头问题
double x=(p1.x-p2.x);
double y=(p1.y-p1.y); //p1.y-p2.y才对
return sqrt(x*x+y*y);
