List<string>排序有关问题

2013-07-08

Liststring排序问题现有一个需求，需要对Liststring里面的Ip进行排序，例如，集合是这样的： Liststring

List<string>排序问题
现有一个需求，需要对List<string>里面的Ip进行排序，
例如，集合是这样的：

 List<string> IpList = new List<string>() {
            "172.16.88.220"
             +"222.73.29.77"
             +"192.168.1.8"
             +"172.16.88.2"
             +"192.168.1.7"
             +"172.16.88.10"
             +"172.16.88.3"
             +"172.16.88.8"
             +"172.16.88.225"
             +"172.16.88.100"
             +"221.130.187.180"
             +"221.130.187.181"
             +"222.73.55.168"
             +"172.16.88.7"
             +"222.73.29.79"
             +"172.16.88.200"
             +"172.16.88.125"
             +"192.168.1.1"
             +"222.73.55.250"
             +"115.236.102.216"
             +"172.17.22.161"
             +"222.73.29.135"
             +"222.73.29.136"
             +"172.17.22.162"
             +"172.16.88.9"
             +"115.238.26.184"
             +"115.238.26.185"
             +"115.238.26.186"
        };

最后想要的顺序是:
115.238.26.184
115.238.26.185
115.238.26.186
115.236.102.216
172.16.88.2
172.16.88.3
172......
192.168.1.1
192.168.1.7
192....
222.73.29.77
222...
请问大家这个如何实现？

             ,"172.17.22.161"
             ,"222.73.29.135"
             ,"222.73.29.136"
             ,"172.17.22.162"
             ,"172.16.88.9"
             ,"115.238.26.184"
             ,"115.238.26.185"
             ,"115.238.26.186"
             ,"115.238.102.216"
        };
            IpList.Sort((s1, s2) =>
            {
                string[] array1 = s1.Split('.');
                string[] array2 = s2.Split('.');
                int index = 0;
                bool equal = true;
                while (equal && index < 4)
                {
                    equal = array1[index] == array2[index];
                    index++;
                }
                return int.Parse(array1[index - 1]).CompareTo(int.Parse(array2[index - 1]));
            });
            foreach (string ip in IpList)
                Console.WriteLine(ip);

------解决方案--------------------

OJ的方法是可以的，在LINQ里同样也可以实现：

                                    ,"192.168.1.8"
                                    ,"172.16.88.2"
                                    ,"192.168.1.7"
                                    ,"172.16.88.10"
                                    ,"172.16.88.3"
                                    ,"172.16.88.8"
                                    ,"172.16.88.225"
                                    ,"172.16.88.100"
                                    ,"221.130.187.180"
                                    ,"221.130.187.181"
                                    ,"222.73.55.168"
                                    ,"172.16.88.7"
                                    ,"222.73.29.79"

                                    ,"172.16.88.200"
                                    ,"172.16.88.125"
                                    ,"192.168.1.1"
                                    ,"222.73.55.250"
                                    ,"115.236.102.216"
                                    ,"172.17.22.161"
                                    ,"222.73.29.135"
                                    ,"222.73.29.136"
                                    ,"172.17.22.162"
                                    ,"172.16.88.9"
                                    ,"115.238.26.184"
                                    ,"115.238.26.185"
                                    ,"115.238.26.186"};

            var result = from x in IpList
                         let 补齐字符串 = string.Join(".", x.Split('.').Select(y => string.Format("{0:C3}", y)).ToArray())
                         orderby 补齐字符串
                         select x;
            foreach (var x in result)
                Console.WriteLine(x);
            Console.ReadKey();
        }

    }

}

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List<string>排序有关问题