C++怎样输出十六进制数?
unsigned char c=-1;
printf("%02x",c);//输出为ff
谁能以C++的cout方式写一个?
[解决办法]
试试：
cout<<hex<<c<<endl;
http://blog.csdn.net/zm_nong/article/details/7721052
[解决办法]
#include <iostream>
int main(void)
{
unsigned char c =-1;
std::cout << std::hex << static_cast<int>(c) << std::endl;
return 0;
}
#include <iostream>
using namespace std;
int main(int argc, char* argv[])
{
unsigned char c = -1;
cout << hex << static_cast<int>(c) <<endl;// 字母小写输出
cout << uppercase << hex << static_cast<int>(c) <<endl;// 字母大写输出
return 0;
}
