帮忙做个题目吧 大神们啊！
求大神们做一下这几道题目吧，希望简洁明了，能运行！谢了！
[解决办法]
用递归求和
int add ( int cur, int n )
{
if ( cur==n ) return 0;
return cur*cur + add(cur+1,n);
}
#include<stdio.h>
int run[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
int ping[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
int puanduan(int nian)
{
int x = 1 ;
if(nian%100==0)
{
if(nian%400==0)
x=0;
}
else if(nian%4==0)
x=0;
return x;
}
int main(void)
{
int i,year,mon,day,year1,mon1,day1,m = 0,n = 0,as,zong = 0,tian;
char s;
/*
输入年月日
*/
printf("输入起始时间（年.月.日）：");
scanf("%d.%d.%d",&year,&mon,&day);
printf("输入终止时间（年.月.日）：");
s = getchar();
scanf("%d.%d.%d",&year1,&mon1,&day1);
/*
判断这中间又几个闰年，几个平年，闰年n+1,平年m+1
*/
for(i = year+1;i < year1;i++)
{
as = puanduan(i);
if(as == 1)
m++;
else
n++;
}
tian = m * 365 + n * 366;
/*
给总天数加上year年的天数
*/
if(puanduan(year))
{
for(i = 0;i < mon;i++)
{
zong = zong + ping[i];
}
zong = 365 - zong;
}
else
{
for(i = 0;i < mon;i++)
{
zong = zong + run[i];
}
zong = 366 - zong;
}
tian = tian + zong;
/*
给总天数加上year1年的天数
*/
if(puanduan(year1))
{
for(i = 0;i < mon;i++)
{
zong = zong + ping[i];
}
}
else
{
for(i = 0;i < mon;i++)
{
zong = zong + run[i];
}
}
tian = tian + zong;
printf("%d年%d月%d日到%d年%d月%d日总共有%d天\n",year,mon,day,year1,mon1,day1,tian);
return 0;
}
