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POST 登陆邮箱 收到token invalid异常,如何解决

2012-12-30 
POST 登陆邮箱 收到token invalid错误,怎么解决这个是post提交的数据POST /webmail/processing.php HTTP/1

POST 登陆邮箱 收到token invalid错误,怎么解决
这个是post提交的数据

POST /webmail/processing.php HTTP/1.1
Host: 10.0.0.166
Connection: keep-alive
Content-Length: 715
Origin: http://10.0.0.166
User-Agent: Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.60 Safari/537.1
Content-type: application/x-www-form-urlencoded
Accept: */*
Referer: http://10.0.0.166/webmail/index.php?mode=logout
Accept-Encoding: gzip,deflate,sdch
Accept-Language: zh-CN,zh;q=0.8
Accept-Charset: GBK,utf-8;q=0.7,*;q=0.3
Cookie: wm_vert_resizer=125; wm_msg_resizer=720; awmcsrftoken=e80e2dfaf05026738195d48d9c1d17f8; PHPWEBMAILSESSID=gfp9sidpl08nl455ik3d7ap8k7

xml=%3C%3Fxml%20version%3D%221.0%22%20encoding%3D%22utf-8%22%3F%3E%3Cwebmail%3E%3Cparam%20name%3D%22action%22%20value%3D%22login%22%20%2F%3E%3Cparam%20name%3D%22request%22%20value%3D%22%22%20%2F%3E%3Cparam%20name%3Dtoken%22%20value%3D%22e80e2dfaf05026738195d48d9c1d17f8%22%2F%3E%3Cparam%20name%3D%22email%22%3E%3C!%5BCDATA%5Ba%40tj.com%5D%5D%3E%3C%2Fparam%3E%3Cparam%20name%3D%22mail_inc_pass%22%3E%3C!%5BCDATA%5B123%5D%5D%3E%3C%2Fparam%3E%3Cparam%20name%3D%22sign_me%22%20value%3D%220%22%2F%3E%3Cparam%20name%3D%22advanced%22%20value%3D%220%22%2F%3E%3Cparam%20name%3D%22domain_name%22%3E%3C!%5BCDATA%5B%5D%5D%3E%3C%2Fparam%3E%3Cparam%20name%3D%22language%22%3E%3C!%5BCDATA%5B%5D%5D%3E%3C%2Fparam%3E%3C%2Fwebmail%3E



收到的包文如下
HTTP/1.1 200 OK
Date: Fri, 02 Nov 2012 06:56:12 GMT
Server: Apache/2.0.63 (Win32) PHP/5.2.14
X-Powered-By: PHP/5.2.14
Expires: Thu, 19 Nov 1981 08:52:00 GMT
Cache-Control: no-store, no-cache, must-revalidate, post-check=0, pre-check=0
Pragma: no-cache
Content-Length: 97
Keep-Alive: timeout=15, max=100
Connection: Keep-Alive
Content-Type: text/xml; charset=utf-8

<?xml version="1.0" encoding="utf-8"?><webmail><error><![CDATA[Token invalid]]></error></webmail>
[解决办法]
无效的token
token%22%20value%3D%22e80e2dfaf05026738195d48d9c1d17f8%22%2F%3E%3C这个token失效了

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