一个SQL查询问题，请高手入场
PROD PRODQTY OPR QTY DATE
A01 100 A 5 2012-01-01
A01 100 B 25 2012-01-02
A01 100 C 35 2012-01-03
A01 100 D 15 2012-01-04
A01 100 E 15 2012-01-05
A01 100 f 10 2012-01-06
A01 100 g 12 2012-01-07
A02 50 Aa 5 2012-02-01
A02 50 Ba 10 2012-02-02
A02 50 Ca 20 2012-02-03
A02 50 Da 16 2012-02-04
A02 50 Ea 15 2012-02-05
A02 50 fa 10 2012-02-06
A02 50 ga 12 2012-02-07
...............
按DATE升序排列，汇总QTY,当汇总数大于或等于前面的PRODQTY(100)的话
那么就取出来那一条记录（当然PROD与PRODQTY的记录都是一致）
如：
PROD PRODQTY OPR QTY DATE
A01 100 E 10 2012-01-05
A02 50 Da 16 2012-02-04
...............
[解决办法]
if object_id('[TB]') is not null drop table [TB]
go
create table [TB] (PROD nvarchar(6),PRODQTY int,OPR nvarchar(4),QTY int,DATE datetime)
insert into [TB]
select 'A01',100,'A',5,'2012-01-01' union all
select 'A01',100,'B',25,'2012-01-02' union all
select 'A01',100,'C',35,'2012-01-03' union all
select 'A01',100,'D',15,'2012-01-04' union all
select 'A01',100,'E',15,'2012-01-05' union all
select 'A01',100,'f',10,'2012-01-06' union all
select 'A01',100,'g',12,'2012-01-07' union all
select 'A02',50,'Aa',5,'2012-02-01' union all
select 'A02',50,'Ba',10,'2012-02-02' union all
select 'A02',50,'Ca',20,'2012-02-03' union all
select 'A02',50,'Da',16,'2012-02-04' union all
select 'A02',50,'Ea',15,'2012-02-05' union all
select 'A02',50,'fa',10,'2012-02-06' union all
select 'A02',50,'ga',12,'2012-02-07'
select * from [TB]
SELECT TB.*
FROM TB
INNER JOIN ( SELECT TOP 1
A.date ,
A.prodqty ,
A.PROD ,
SUM(B.QTY) AS qty
FROM dbo.TB A
INNER JOIN TB B ON A.date >= B.date
GROUP BY A.date ,
A.prodqty ,
A.PROD
HAVING SUM(B.QTY) <= A.prodqty
ORDER BY a.date DESC
) T ON T.date = TB.date
AND T.prod = TB.prod
/*
A01100E152012-01-05 00:00:00.000*/