C++实现汽车订票系统（C++课程设计）
#include<iostream>#include<fstream>#include<cstring>#include<iomanip>#define Maxsize 100using namespace std;struct Route{char number[20];char startandreach[20];char type[20];char longroute[20];char time[20];double price;int sitnumber;int save;intsale;};struct Ticketnews{ char type[20]; char time[20]; int booked; int remained;};struct Booknews{char name[20];char identitycard[20];char number[20];char date[20];char road[20];int sitnumber;};void Match(Route L1[],Ticketnews L2[],int n)//票务信息保存{ofstream outfile("票务信息.txt",ios::out); if (!outfile){ cerr<<"open error!"<<endl; exit(1);}int i;for(i=0;i<n;i++){strcpy(L2[i].type,L1[i].type);strcpy(L2[i].time,L1[i].time);L2[i].booked=L1[i].sale;L2[i].remained=L1[i].save;outfile<<L2[i].type<<" "<<L2[i].time<<" "<<L2[i].booked<<" "<<L2[i].remained<<endl;}outfile.close();}int Book(Booknews &L1,Route &L2,int s)//这里一定要是参数传递{ofstream outfile("买票客户信息.txt",ios::app);//怎么可以重复的写入订票人的数据 if (!outfile){ cerr<<"open error!"<<endl; exit(1);}cout<<"请输入订票信息:"<<endl;cout<<"姓名:";cin>>L1.name;cout<<"身份证:";cin>>L1.identitycard;cout<<"车次:";cin>>L1.number;cout<<"日期:";cin>>L1.date;cout<<"路线:";cin>>L1.road;L2.sale++;L2.save--;L1.sitnumber=L2.sale;cout<<"订票信息为:"<<endl;cout<<"姓名:"<<L1.name<<endl<<"身份证:"<<L1.identitycard<<endl<<"车次:"<<L1.number<<endl<<"日期:"<<L1.date<<endl<<"座位号:"<<L1.sitnumber<<endl<<"路线:"<<L1.road<<endl; outfile<<L1.name<<" "<<L1.identitycard<<" "<<L1.number<<" "<<L1.date<<" "<<L1.sitnumber<<" "<<L1.road<<endl;outfile.close();s++;return s;}int Return(Booknews L1[],int s){Booknews L;con:cout<<"请输入退票者姓名，身份证";cin>>L.name>>L.identitycard;int i;for(i=0;i<s;i++){if(((strcmp(L.name,L1[i].name))&&(strcmp(L.identitycard,L1[i].identitycard)))){cout<<"这个人没有订票!"<<endl;return 0;}else{int j=i;cout<<"该订票者的信息为:";cout<<"姓名:"<<L1[i].name<<endl;cout<<"身份证:"<<L1[i].identitycard<<endl;cout<<"车次:"<<L1[i].number<<endl;cout<<"订票日期:"<<L1[i].date<<endl;cout<<"座位号:"<<L1[i].sitnumber<<endl;cout<<"路线:"<<L1[i].road<<endl;cout<<"以上信息是否符合?符合请按1，不符合请按2:";int k;cin>>k;if(k==2) goto con;else/*cout<<"输入订票者的车次,座位号和日期:";cin>>L.number>>L.sitnumber>>L.date;for(i=L.sitnumber-1;i<s;i++){strcpy(L1[i].name,L1[i+1].name);strcpy(L1[i].identitycard,L1[i+1].identitycard);strcpy(L1[i].number,L1[i+1].number);strcpy(L1[i].date,L1[i+1].date);L1[i].sitnumber=L1[i+1].sitnumber;cout<<"退票成功!"<<endl;}*/{for(;i<s;i++)//删除退票者的信息{strcpy(L1[i].name,L1[i+1].name);strcpy(L1[i].identitycard,L1[i+1].identitycard);strcpy(L1[i].number,L1[i+1].number);strcpy(L1[i].date,L1[i+1].date);L1[i].sitnumber=L1[i+1].sitnumber;}cout<<"退票成功!"<<endl;ofstream outfile("买票客户信息.txt",ios::out);if(!outfile){cerr<<"open error!"<<endl;exit(1);}for(i=0;i<j;i++){outfile<<L1[i].name<<" "<<L1[i].identitycard<<" "<<L1[i].number<<" "<<L1[i].date<<" "<<L1[i].sitnumber<<endl;}outfile.close();}return j;}}}int main(){ifstream infile("所有车次路线信息.txt",ios::in);if (!infile){ cerr<<"open error!"<<endl; exit(1);}ifstream infile1("买票客户信息.txt",ios::in);//怎么可以重复的写入订票人的数据 if (!infile1){ cerr<<"open error!"<<endl; exit(1);}int n,i,n1,s,j; infile>>n; infile1>>s;infile1.close(); Route route[Maxsize]; Ticketnews ticketnews[Maxsize];Booknews booknews[Maxsize]; for(i=0;i<n;i++) { infile>>route[i].number>>route[i].startandreach>>route[i].type>>route[i].longroute>>route[i].time>>route[i].price>>route[i].sitnumber>>route[i].save>>route[i].sale; } cout<<"输出所有汽车路线为:"<<endl; cout<<"车次"<<setw(7)<<"路线"<<setw(18)<<"车型"<<setw(12)<<"路线长度"<<setw(7)<<"时间"<<setw(14)<<"价格"<<setw(8)<<"座位"<<setw(5)<<"剩票"<<setw(5)<<"卖票"<<endl; for(i=0;i<n;i++) { cout<<route[i].number<<setw(20)<<route[i].startandreach<<setw(12)<<route[i].type<<setw(8)<<route[i].longroute<<setw(15)<<route[i].time<<setw(8)<< route[i].price<<setw(4)<<route[i].sitnumber<<setw(4)<<route[i].save<<setw(4)<<route[i].sale<<endl; //cout<<route[i].number<<" "<<route[i].startandreach<<" "<<route[i].type<<" "<<route[i].longroute<<" "<<route[i].time<<" "<<// route[i].price<<" "<<route[i].sitnumber<<" "<<route[i].save<<" "<<route[i].sale<<endl; }Match(route,ticketnews,n);cout<<"主菜单为:"<<endl;con:cout<<"1 为订票，2 为退票，3 为改变路线，4为查询订票情况，5为退出该系统，请根据你所要实现的功能输入相应的数字:";cin>>n1;switch(n1){case 1:{con1:cout<<"请输入你要订票的车次:";cin>>booknews[s].number;bool flag(true);//一定要用bool变量控制for(i=0;i<n;i++){if(!(strcmp(booknews[s].number,route[i].number))&&(route[i].save!=0)){//定义一个变量是否需要订票flag = false;cout<<booknews[s].number<<"车次还有票是否需要订票，是就输入yes，否就输入no:";char k1[5];con3:cin>>k1;if(!strcmp(k1,"yes")){s=Book(booknews[s],route[i],s);}elsebreak;cout<<"是否还要订票，是就输入yes，不是就输入no:";goto con3;}}if(flag){cout<<"你输入的车次不存在，请重新输入!"<<endl;goto con1;}ofstream outfile("买票客户信息.txt",ios::out||ios::app); if (!outfile){ cerr<<"open error!"<<endl; exit(1);} outfile<<s<<endl;//一定要加一行endl，在另一行添加才可 outfile.close();cout<<"返回主菜单请按1,否则请按2:";int kkk;cin>>kkk;if(kkk==1)goto con;elsebreak;}case 2:{if(s==0){cout<<"目前没有人订票，不能退票!"<<endl;goto con;}else{j=Return(booknews,s);s--; route[j].sale--;route[j].save++;cout<<"返回主菜单请按1，退出请按2:";int kk1;cin>>kk1;if(kk1==1)goto con;}ofstream outfile("买票客户信息.txt",ios::out||ios::app);//怎么可以重复的写入订票人的数据 if (!outfile){ cerr<<"open error!"<<endl; exit(1);} outfile<<s<<endl; outfile.close();break;}case 3://用指针指向文件？？{cout<<"请输入管理员密码:";int code;cin>>code;if(code==123)//记住密码{ con4:cout<<"请根据A为增加路线，B为删除路线，C为修改汽车路线信息输入相应的字母:"; char z;cin>>z; if(z=='A') { infile.close(); con5:n++;//注意con5要指对地方 ofstream outfile("所有车次路线信息.txt",ios::out||ios::app); if (!outfile) { cerr<<"open error!"<<endl; exit(1); } outfile<<n;//输出过后要在把n输进去？？？？ //infile>>n; if(!outfile.eof())//指向文件末尾 outfile.seekp(0,ios::end);//outfile<<endl;cout<<"请输入增加路线的所有数据:"<<endl; cout<<"车次:";cin>>route[n-1].number; cout<<"路线:";cin>>route[n-1].startandreach; cout<<"车辆类型:";cin>>route[n-1].type; cout<<"里程:";cin>>route[n-1].longroute; cout<<"时间:";cin>>route[n-1].time; cout<<"票价:";cin>>route[n-1].price; cout<<"座位数:";cin>>route[n-1].sitnumber; cout<<"剩余票数:";cin>>route[n-1].save; cout<<"卖票数:";cin>>route[n-1].sale; outfile<<route[n-1].number<<" "<<route[n-1].startandreach<<" "<<route[n-1].type<<" "<<route[n-1].longroute<<" " <<route[n-1].time<<" "<<route[n-1].price<<" "<<route[n-1].sitnumber<<" "<<route[n-1].save<<" "<<route[n-1].sale<<endl; outfile.close(); cout<<"是否还要增加路线，是请输入yes，退出请输入no:"; char kk3[5]; cin>>kk3; if(strcmp(kk3,"no")) goto con5; }else{if(z=='B'){con6:cout<<"请输入你要删除的车次路线:"; char z1[20];int z2=-1; cin>>z1; for(i=0;i<n;i++) { if(!strcmp(z1,route[i].number)) { z2=i; break; } } if(z2>0) {for(;z2<n-1;z2++){ strcpy(route[z2].number,route[z2+1].number); strcpy(route[z2].startandreach,route[z2+1].startandreach); strcpy(route[z2].type,route[z2+1].type); strcpy(route[z2].longroute,route[z2+1].longroute); strcpy(route[z2].time,route[z2+1].time); route[z2].price=route[z2+1].price; route[z2].sitnumber=route[z2+1].sitnumber; route[z2].save=route[z2+1].save; route[z2].sale=route[z2+1].sale;}n--;ofstream outfile("所有车次路线信息.txt",ios::out); if (!outfile) { cerr<<"open error!"<<endl; exit(1); } outfile<<n<<endl;for(i=0;i<n;i++){outfile<<route[i].number<<" "<<route[i].startandreach<<" "<<route[i].type<<" "<<route[i].longroute<<" "<<route[i].time<<" "<< route[i].price<<" "<<route[i].sitnumber<<" "<<route[i].save<<" "<<route[i].sale<<endl;}outfile.close();con7:cout<<"是否还要删除路线，是就输入yes，否就输入no:";char kk4[5];cin>>kk4;if(!strcmp(kk4,"yes"))goto con6;elseif(!strcmp(kk4,"no"))break;elseif(strcmp(kk4,"yes")) {cout<<"你输入的单词不符合要求，请重新输入:";goto con7;} } } else { if(z=='C'){con2:cout<<"请输入你要修改的路线:";char k[20],k2[20];int kk;cin>>k;for(i=0;i<n;i++){if(!strcmp(k,route[i].startandreach)) { cout<<"修改路线为:"; cin>>k2; strcpy(route[i].startandreach,k2); /*cout<<"是否还要修改，是就输入yes，否就输入no:";当想要把重复的路线修改时，就要用到的程序段 char kk4[5]; cin>>kk4; if(strcmp(kk4,"yes")) break;*/ }ofstream outfile("所有车次路线信息.txt",ios::out); if (!outfile) { cerr<<"open error!"<<endl; exit(1); } outfile<<n<<endl;for(i=0;i<n;i++){outfile<<route[i].number<<" "<<route[i].startandreach<<" "<<route[i].type<<" "<<route[i].longroute<<" "<<route[i].time<<" "<< route[i].price<<" "<<route[i].sitnumber<<" "<<route[i].save<<" "<<route[i].sale<<endl;}outfile.close();}break;con8:cout<<"是否还需要修改，是就选1，不是就选2:";cin>>kk;if(kk==1)goto con2;elseif(kk==2)break;else {cout<<"你输入的数字不符合要求，请重新输入:"; goto con8;}} else{ cout<<"你输入的数字不符合要求,请重新输入:"; goto con4;} }}}else{cout<<"你所输入的密码错误，返回主菜单请按1，退出请按2:";int kk2;cin>>kk2;if(kk2==2)return 0;elsegoto con;}break;}case 4:{char k3[10],k4[20];cout<<"请输入用户名和身份证号:";cin>>k3>>k4;for(i=0;i<s;i++){if(!(strcmp(k3,booknews[i].name)&&strcmp(k4,booknews[i].identitycard))){cout<<"你的订票信息为:"<<endl;cout<<"姓名:"<<booknews[i].name<<endl;cout<<"身份证号:"<<booknews[i].identitycard<<endl;cout<<"车次:"<<booknews[i].number<<endl;cout<<"座位号:"<<booknews[i].sitnumber<<endl;cout<<"日期:"<<booknews[i].date<<endl;}}}return 0;case 5:{return 0;}default:{cout<<"你所选的功能不存在，请重新再选择!"<<endl;goto con;}} cout<<"输出所有汽车路线为:"<<endl; for(i=0;i<n;i++) {cout<<route[i].number<<setw(20)<<route[i].startandreach<<setw(12)<<route[i].type<<setw(8)<<route[i].longroute<<setw(15)<<route[i].time<<setw(8)<< route[i].price<<setw(4)<<route[i].sitnumber<<setw(4)<<route[i].save<<setw(4)<<route[i].sale<<endl; /*cout<<route[i].number<<" "<<route[i].startandreach<<" "<<route[i].type<<" "<<route[i].longroute<<" "<<route[i].time<<" "<< route[i].price<<" "<<route[i].sitnumber<<" "<<route[i].save<<" "<<route[i].sale<<endl;*/ }//goto con;return 0;}
自己设置的票务信息
quickplane 12:00--19:00 0 100
quickplane 12:00--19:00 0 100
train 12:00--19:00 0 100
quickplane 12:00--19:00 0 100
train 12:00--19:00 0 100
quickplane 12:00--19:00 0 100
car 12:00--19:00 0 100
car 12:00--19:00 0 100
train 12:00--19:00 0 100
quickplane 12:00--19:00 0 100
car 12:00--19:00 0 100
car 12:00--19:00 0 100
car 4:00--8:00 0 35
car 8:00--9:00 0 45
car 9:00--19:00 0 48
car 9:00--19:00 0 45
所有车次的路线信息
16
A000 Beijing--Nanchang quickplane 1000Km 12:00--19:00 456.25 100 100 0
A001 Beijing--Nanchang quickplane 1000Km 12:00--19:00 456.25 100 100 0
A002 Beijing--Nanchang train 1000Km 12:00--19:00 456.25 100 100 0
A003 Beijing--Nanchang quickplane 1000Km 12:00--19:00 456.25 100 100 0
A004 Beijing--Nanchang train 1000Km 12:00--19:00 456.25 100 100 0
A005 Beijing--Nanchang quickplane 1000Km 12:00--19:00 456.25 100 100 0
A006 Beijing--Nanchang car 1000Km 12:00--19:00 456.25 100 100 0
A007 Beijing--Nanchang car 1000Km 12:00--19:00 456.25 100 100 0
A008 Beijing--Nanchang train 1000Km 12:00--19:00 456.25 100 100 0
A009 Beijing--Nanchang quickplane 1000Km 12:00--19:00 456.25 100 100 0
A010 Beijing--Nanchang car 1000Km 12:00--19:00 456.25 100 100 0
A011 Beijing--Nanchang car 1000Km 12:00--19:00 456.25 100 100 0
A012 J--P car 456km 4:00--8:00 45 35 35 0
A013 JJ--PP car 456km 8:00--9:00 45.2 45 45 0
A013 pp--ll car 489km 9:00--19:00 45.32 48 48 0
A014 car car 456km 9:00--19:00 45.2 45 45 0