webservice 入门例子 源代码
?? ? 最近准备考试：将webservice 充充电，本想配置一遍，在网上资料，资源虽多，没有几个能成功的，还没有几个有原代码的，可能是自己理解能力有限，摸索了一段时间，终于调通了webservice ！
? ? 在此为想学习webservice同仁们提供一个入门例子
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?1、新建一个web project，如下面的例子为Storm
?2、在工程中目录如下图所示
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Storm.
│? .classpath
│? .project
│? index.html
│? tree.txt
│ ?
├─.settings
│????? com.spket.js.prefs
│????? org.eclipse.core.resources.prefs
│???? ?
├─src
│? └─com
│????? │? TestDWR.java
│????? │? TestWebService.java
│????? │ ?
│????? └─service
│????????????? HelloWorld.java
│???????????? ?
└─WEB-INF
??? │? server-config.wsdd
??? │? web.xml
??? │ ?
??? ├─attachments
??? ├─classes
??? │? └─com
??? │????? │? TestDWR.class
??? │????? │? TestWebService.class
??? │????? │ ?
??? │????? └─service
??? │????????????? HelloWorld.class
??? │???????????? ?
??? └─lib
??????????? axis-ant.jar
??????????? axis.jar
??????????? commons-discovery-0.2.jar
??????????? commons-logging-1.0.4.jar
??????????? jaxrpc.jar
??????????? log4j-1.2.8.jar
??????????? saaj.jar
??????????? wsdl4j-1.5.1.jar
3、编写java类
public class HelloWorld {private String name = "qingfeng";public String getName(){return name;}public String hiHello(String name){return "Hi:" + name;}}?4、修改web.xml
<?xml version="1.0" encoding="UTF-8"?><web-app xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4"> <servlet> <servlet-name>AxisServlet</servlet-name> <servlet-class>org.apache.axis.transport.http.AxisServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>AxisServlet</servlet-name> <url-pattern>/services/*</url-pattern> </servlet-mapping> <welcome-file-list> <welcome-file>index.jsp</welcome-file> <welcome-file>index.html</welcome-file> </welcome-file-list></web-app>
?5、修改 server-config.wsdd文件，与web.xml同一级目录，内容如下，在别面拷贝一个，修改自己类及方法
<?xml version="1.0" encoding="UTF-8"?><deployment xmlns="http://xml.apache.org/axis/wsdd/" xmlns:java="http://xml.apache.org/axis/wsdd/providers/java"> <globalConfiguration> <parameter name="sendMultiRefs" value="true"/> <parameter name="disablePrettyXML" value="true"/> <parameter name="dotNetSoapEncFix" value="true"/> <parameter name="enableNamespacePrefixOptimization" value="false"/> <parameter name="sendXMLDeclaration" value="true"/> <parameter name="sendXsiTypes" value="true"/> <parameter name="attachments.implementation" value="org.apache.axis.attachments.AttachmentsImpl"/></globalConfiguration> <handler type="java:org.apache.axis.handlers.http.URLMapper" name="URLMapper"/> <service name="hello" provider="java:RPC"> <parameter name="className" value="com.service.HelloWorld" /> <parameter name="allowedMethods" value="*" /> </service> <service name="test" provider="java:RPC"> <parameter name="className" value="com.TestDWR" /> <parameter name="allowedMethods" value="*" /> </service> <transport name="http"> <requestFlow> <handler type="URLMapper"/> </requestFlow> </transport> </deployment>
6、将相关的jar加上，如上述目录所示，将工程布置到tomcat中，
7、访问发布的路径，如我本地为：http://localhost:8080/Storm/services
8、若在IE中，看到如下所示，就表明成功了
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And now... Some Services
hello (wsdl)
helloNamegetNametest? (wsdl)
getAge9、下面我们再写一个测试类，提供外界访问，在工程目录中com.TestWebService类，代码如下所示
package com;import javax.xml.rpc.ServiceException;import org.apache.axis.client.Call;import org.apache.axis.client.Service;public class TestWebService {public static void test2() {String url = "http://localhost:8080/Storm/services/hello";Service service = new Service();Call call;String name = "东东和范范";try {call = (Call) service.createCall();call.setTargetEndpointAddress(new java.net.URL(url));call.setOperationName("helloName");String res = (String) call.invoke(new Object[] { name });System.out.println(res);} catch (ServiceException e) {e.printStackTrace();} catch (Exception e) {e.printStackTrace();}}/** * @param args */public static void main(String[] args) {test2();}}?10、在控制台输出【hello:东东和范范】表明成功。
?11、附上整个项目源代码
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1 楼 dwbin 2011-03-25 wsdl还有一种比较简单的发布方式，就是类不要包名，直接放在根目录下面，然后使用/Contxtpath/className/methodName进行访问就行了。