求高人指点 汇编四则运算程序除法为什么总提示溢出
下面是我编写四则运算程序，除法一直提示溢出（2除2都溢出），想编出带余数的，求高人指点啊！！（由于刚刚开始学，问题可能比较幼稚，请不要见笑！）
str00macrost
leadx,st
movah,09h
int21h
endm
;============================
datasegment
xdw?
ydw?
symboldb?
zdw?
contdb?
jiemiandb'=================================',13,10
db'= size system =',13,10
db'=1.add 2.sub 3.mul 4.div 5.exit =',13,10
db'=================================','$'
str0db13,10,'x=$'
str1db13,10,'y=$'
str2db13,10,'input(+-*/):$'
str3db'Not a yunsuanfu'
str4db13,10,'z=$'
str5db13,10,'continue(y/n):$'
str6db13,10,'overfolw$'
str7db13,10,'yushu:$'
dataends
;===========================
codesegment
assume cs:code,ds:data
mainproc
start:
movax,data
movds,ax
str00jiemian
begin:str00str0
calldecibin
movx,bx
str00str1
calldecibin
movy,bx
callyunsuan
exit:
movah,4ch
int21h
mainendp
;==============================
yunsuanproc
str00str2
pushax
movah,01h
int21h
movdx,0
movdl,al
popax
movsymbol,dl
;str00str5
cmpsymbol,'+'
jejia
cmpsymbol,'-'
jejian0
cmpsymbol,'*'
jecheng
cmpsymbol,'/'
jechu
str00str3
ret
jia:
movax,x
addax,y
movz,ax
jmpjieguo
jian0:
movax,x
movbx,y
cmpax,bx
jljian1
jian1:
xchgax,bx
subax,bx
movz,ax
jmpjieguo0
jian2:
movax,x
subax,y
movz,ax
jmpjieguo
cheng:
movax,x
muly
cmpdx,0
jgerror
movz,ax
jmpjieguo
chu:
pushax
pushbx
pushdx
movax,x
divy
cmpdx,0
jnzjieguo1
movz,ax
popax
popbx
popdx
jmpjieguo
jieguo:
str00str4
movbx,z
callbinidec
jmpcontinue
jieguo0:
str00str4
movah,02h
movdl,'-'
int21h
movbx,z
callbinidec
jmpcontinue
jieguo1:
str00str4
movbx,z
callbinidec
str00str7
movdh,0
movah,02h
int21h
jmpcontinue
continue:
str00str5
pushax
movah,01h
int21h
movdx,0
movdl,al
popax
movcont,dl
cmpcont,'y'
jzbegin
cmpcont,'n'
jzexit
error:
str00str6
jmpcontinue
yunsuanendp
;==============================
decibinproc
movbx,0
rulop:
movah,01h
int21h
cmpal,30h
jlruexit
cmpal,39h
jgruexit
subal,30h
cbw
xchgax,bx
movcx,10
mulcx
addbx,ax
jmprulop
ruexit:
ret
decibinendp
;==============================
binidecproc
cmpbx,0
jnzclop0
moval,02h
movdl,'0'
adddl,30h
int21h
jmpchuexit
clop0:movcx,5
clop1:movax,bx
movdx,0
movsi,10
divsi
pushdx
movbx,ax
loopclop1
movbp,0
movcx,5
clop2:popdx
cmpdl,0
jnzclop3
cmpbp,0
jzclop4
clop3:
movbp,1
movah,02h
adddl,30h
int21h
clop4:
loopclop2
chuexit:
ret
binidecendp
;========================================
codeends
;===============================
end main
[解决办法]
已经解决了！！
