No embedded stylesheet instruction for file:奇怪的错误
08:09:43,395 INFO [main] Main - javax.xml.transform.TransformerFactory=null08:09:43,398 INFO [main] Main - java.endorsed.dirs=/Library/Java/JavaVirtualMachines/jdk1.7.0_10.jdk/Contents/Home/jre/lib/endorsed08:09:43,407 INFO [main] Main - launchFile: /Users/lishupeng/spaces/eclipsespaces/.metadata/.plugins/org.eclipse.wst.xsl.jaxp.launching/launch/launch.xml08:09:44,618 FATAL [main] Main - No embedded stylesheet instruction for file: file:/Users/lishupeng/spaces/eclipsespaces/.../dao/User.xmlorg.eclipse.wst.xsl.jaxp.debug.invoker.TransformationException: No embedded stylesheet instruction for file: file:/Users/lishupeng/spaces/eclipsespaces/.../dao/User.xmlat org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.transform(JAXPSAXProcessorInvoker.java:225)at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.transform(JAXPSAXProcessorInvoker.java:186)at org.eclipse.wst.xsl.jaxp.debug.invoker.internal.Main.main(Main.java:73)Caused by: org.eclipse.wst.xsl.jaxp.debug.invoker.TransformationException: No embedded stylesheet instruction for file: file:/Users/lishupeng/spaces/eclipsespaces/.../dao/User.xmlat org.eclipse.wst.xsl.jaxp.debug.invoker.internal.JAXPSAXProcessorInvoker.transform(JAXPSAXProcessorInvoker.java:214)... 2 more
?百思不得其解，分析了下发现main的提示入口竟然是xml文件，原来是我为了图快捷，直接在xml里面点了运行，没有切换到源代码去~解决
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看来eclipse运行时是根据当前所在文件的类型来寻找入口点的~
