正则表述提取标签属性值

正则表达提取标签属性值
如何用正则表达是提title的值“The Amazing Spider-Man (2012)”呢？
我自己是用两次preg_split取的，但感觉很低效，有没有朋友给点思路呢？

HTML code

<td class="image">    <a href="/title/tt0948470/" title="The Amazing Spider-Man (2012)"><img src="http://ia.media-imdb.com/images/M/MV5BMjMyOTM4MDMxNV5BMl5BanBnXkFtZTcwNjIyNzExOA@@._V1._SX54_CR0,0,54,74_.jpg" height="74" width="54" alt="The Amazing Spider-Man (2012)" title="The Amazing Spider-Man (2012)"></a>  </td>

PHP code

<?php$str='<td class="image">    <a href="/title/tt0948470/" title="The Amazing Spider-Man (2012)"><img src="http://ia.media-imdb.com/images/M/MV5BMjMyOTM4MDMxNV5BMl5BanBnXkFtZTcwNjIyNzExOA@@._V1._SX54_CR0,0,54,74_.jpg" height="74" width="54" alt="The Amazing Spider-Man (2012)" title="The Amazing Spider-Man (2012)"></a>    <a href="/title/tt0948470/" title="The Amazing Spider-Man (2012)">  </td>';$patten = '/title="(.*)"/Uis';if (preg_match ( $patten, $str, $array )) {print_r($array);}echo "<br>";$patten1 = '/<a href=".*" title="(.*)">/Uis';if (preg_match_all ( $patten1, $str, $array1 )) {print_r($array1[1]);}?>
[解决办法]
PHP code
$string='<td class="image"><a href="/title/tt0948470/" title="The Amazing Spider-Man (2012)1"><img src="http://ia.media-imdb.com/images/M/MV5BMjMyOTM4MDMxNV5BMl5BanBnXkFtZTcwNjIyNzExOA@@._V1._SX54_CR0,0,54,74_.jpg" height="74" width="54" alt="The Amazing Spider-Man (2012)" title="The Amazing Spider-Man (2012)3"></a><a href="/title/tt0948470/" title="The Amazing Spider-Man (2012)2"></td>';     if (preg_match_all ( '/(?<=\s)title="(.*)"/Ui', $string, $arr )) {        var_dump($arr);    }    /*        <br>array(2) {  [0]=>  array(3) {    [0]=>    string(38) "title="The Amazing Spider-Man (2012)1""    [1]=>    string(38) "title="The Amazing Spider-Man (2012)3""    [2]=>    string(38) "title="The Amazing Spider-Man (2012)2""  }  [1]=>  array(3) {    [0]=>    string(30) "The Amazing Spider-Man (2012)1"    [1]=>    string(30) "The Amazing Spider-Man (2012)3"    [2]=>    string(30) "The Amazing Spider-Man (2012)2"  }}    */