怎样让c#中的程序在设计模式上进行调试执行

怎样让c#中的程序在设计模式下进行调试执行

怎样让c#中的程序在设计模式下进行调试执行

在设计系统时，一般需要运行中进行调试执行，我记得过去看过一个在设计模式下就可以执行Button_Click事件下的例子。
请大虾能能否指点下,或给个例子

Tks!

[解决办法]
You need to override the designer's GetHitTest() method, so the designer can route the click event to your control:

C# code

using System;using System.ComponentModel;using System.Drawing;using System.Windows.Forms;using System.Windows.Forms.Design;                             //<---namespace WindowsFormsApplication1{    [Designer(typeof(MyDesigner))]                             //<---    public partial class UserControl1 : UserControl    {        public UserControl1()        {            InitializeComponent();        }        private void button1_Click(object sender, EventArgs e)        {            if( this.DesignMode )            {                MessageBox.Show("Click in design mode");            }        }    }    class MyDesigner : ControlDesigner    {        protected override bool GetHitTest(Point point)         //<---        {            point = this.Control.PointToClient(point);            foreach (Control c in this.Control.Controls)            {                if (c.Bounds.Contains(point))                {                    return true;                }            }            return base.GetHitTest(point);        }    }}
[解决办法]
探讨

You need to override the designer's GetHitTest() method, so the designer can route the click event to your control: 


C# code
using System;
using System.ComponentModel;
using System.Drawing;
using System.Windows.Forms;
using System.Windows.Forms.Design;                             //<---

namespace WindowsFormsApplication1
{
    [Designer(typeof(MyDesigner))]                        …

[解决办法]
探讨

You need to override the designer's GetHitTest() method, so the designer can route the click event to your control: 


C# code
using System;
using System.ComponentModel;
using System.Drawing;
using System.Windows.Forms;
using System.Windows.Forms.Design;                             //<---

namespace WindowsFormsApplication1
{
    [Designer(typeof(MyDesigner))]                        …

[解决办法]
探讨

在需要调试的代码部分插入断点，然后再按F5键就进入的调试模式!

[解决办法]
探讨

You need to override the designer's GetHitTest() method, so the designer can route the click event to your control: 


C# code
using System;
using System.ComponentModel;
using System.Drawing;
using System.Windows.Forms;
using System.Windows.Forms.Design;                             //<---

namespace WindowsFormsApplication1
{
    [Designer(typeof(MyDesigner))]                        …

[解决办法]
实际上可以不用F5就可以调试滴

可以直接在即时窗口里，动态new一个对象，然后就可以直接调用这个对象的方法

不过这种东西对无界面的纯逻辑代码比较好，而带事件的UI，这种方式就有问题了，因为少了鼠标交互，所以一些与客户交互性的代码比较难验证
[解决办法]
仔细看了下，代码目的不一样，再试了下，你的代码是对的。。。。