WORD(BYTE(pBuf[nPos]));解决办法

WORD(BYTE(pBuf[nPos]));
这句话什么什么意思？

C/C++ code

WORD CRC16_LH(unsigned char* pBuf,int nLength){    WORD nCRC = 0x0000;    WORD ch;    WORD tmp;    int nIndex;    int nPos=0;    while(nLength>0)    {        nLength -= 1;        ch = WORD(BYTE(pBuf[nPos]));        nPos += 1;        for(nIndex = 0;nIndex<=7;nIndex++)        {    tmp = nCRC & 0x8000;        nCRC <<= 1;        if(ch & 0x80)            nCRC += 1;        if(tmp)            nCRC = nCRC ^ 0x1021;        ch <<= 1;        }    }    return nCRC;} 

C/C++ code

typedef unsigned short WORD;typedef unsigned char BYTE;
[解决办法]
WORD(BYTE(pBuf[nPos]));
强制转换
[解决办法]
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从你的代码看, 
WORD(BYTE(pBuf[nPos]));
这个根本就没有特殊的意思.
 
typedef unsigned short WORD;
typedef unsigned char BYTE;

4楼说的这个已经很明显了. 那一堆强制转换就没什么意思义