关于quartz 2.x 一些记录
功能需要 审计（即对不同规则的定制的东西进行轮巡)如果每一个轮询都是一个任务的话，则很影响效率，所以将其建成就一个任务，检查最小时间，将最小时间作为下次执行的时间，根据时间和任务传递过来的参数判断执行的是那个规则。
所以此处的任务应当满足，时间的更新，datamap参数的更新。
log.info("------- Initializing ----------------------"); SchedulerFactory sf = new StdSchedulerFactory(); Scheduler sched = sf.getScheduler(); System.out.println(sched.getSchedulerName()); log.info("------- Initialization Complete -----------"); Date runTime = DateBuilder.evenSecondDate(new Date()); log.info("------- Scheduling Job -------------------"); //job1、trigger1 用来审计 JobDetail job1 = JobBuilder.newJob(DelSchedule.class).withIdentity("job1", "group1").build(); Trigger trigger1 = TriggerBuilder.newTrigger().withIdentity("trigger1", "group1").startAt(runTime).withSchedule(SimpleScheduleBuilder.simpleSchedule().repeatHourlyForever(12)).build();???? 具体更新操作
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SchedulerFactory schedulerFactory = new StdSchedulerFactory(); Scheduler scheduler = schedulerFactory.getScheduler("DefaultQuartzScheduler"); JobDetail jobDetail = scheduler.getJobDetail(JobKey.jobKey("job1", "group1")); // retrieve the trigger Trigger oldTrigger = scheduler.getTriggersOfJob(JobKey.jobKey("job1", "group1")).get(0); // obtain a builder that would produce the trigger TriggerBuilder tb = oldTrigger.getTriggerBuilder(); // update the schedule associated with the builder, and build the new trigger // (other builder methods could be called, to change the trigger in any desired way) Trigger newTrigger = TriggerBuilder.newTrigger().withIdentity("trigger1", "group1").startAt(minDate).withSchedule(SimpleScheduleBuilder.simpleSchedule().repeatHourlyForever(12)).build(); jobDetail.getJobDataMap().put("id",newId); scheduler.addJob(jobDetail, true); scheduler.rescheduleJob(oldTrigger.getKey(), newTrigger);?
对于其它一些需求或深入了解，可以进入官网详细了解http://quartz-scheduler.org/documentation/quartz-2.1.x/quick-start
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