关于JavaScript中计算精度丢失的问题(二)
3.3加减乘除
对指定数字进行四舍五入可以通过floor/ceil或者正则表达式达到舍入的目的,那么四则运算是不是也可以升级成计算机能够精确识别的整数来计算,计算完毕再降级呢?这个答案是肯定的,我们先来看看加法:
Number.prototype.add = function(arg){ var n, n1, n2, s, s1, s2, ps; s1 = this.toString(); ps = s1.split('.'); n1 = ps[1] ? ps[1].length : 0; s2 = arg.toString(); ps = s2.split('.'); n2 = ps[1] ? ps[1].length : 0; n = n1 > n2 ? n1 : n2; s = Number(s1.movePoint(n)) + Number(s2.movePoint(n)); s = s.toString().movePoint(-n); return Number(s);}
Number.prototype.sub = function(arg){ var n, n1, n2, s, s1, s2, ps; s1 = this.toString(); ps = s1.split('.'); n1 = ps[1] ? ps[1].length : 0; s2 = arg.toString(); ps = s2.split('.'); n2 = ps[1] ? ps[1].length : 0; n = n1 > n2 ? n1 : n2; s = Number(s1.movePoint(n)) - Number(s2.movePoint(n)); s = s.toString().movePoint(-n); return Number(s);}
Number.prototype.mul = function(arg){ var n, n1, n2, s, s1, s2, ps; s1 = this.toString(); ps = s1.split('.'); n1 = ps[1] ? ps[1].length : 0; s2 = arg.toString(); ps = s2.split('.'); n2 = ps[1] ? ps[1].length : 0; n = n1 + n2; s = Number(s1.replace('.', '')) * Number(s2.replace('.', '')); s = s.toString().movePoint(-n); return Number(s);}
Number.prototype.div = function(arg){ var n, n1, n2, s, s1, s2, ps; s1 = this.toString(); ps = s1.split('.'); n1 = ps[1] ? ps[1].length : 0; s2 = arg.toString(); ps = s2.split('.'); n2 = ps[1] ? ps[1].length : 0; n = n1 - n2; s = Number(s1.replace('.', '')) / Number(s2.replace('.', '')); s = s.toString().movePoint(-n); return Number(s);}