递归回来N的二进制中1的个数

递归返回N的二进制中1的个数
方法1:

public static int getBinary(int num) {if (0==num) {return 0;} else {if (0==num%2) {return getBinary(num/2);} else {return getBinary(num/2)+1;}}}

public static int getBinary(int num) {if (0==num) {return 0;} else {if (0==num%2) {return getBinary(num>>1);} else {return getBinary(num>>1)+1;}}}