javascript 如何 处理日期var s1 2007-01-01var s2 2007-12-31s1 s1.replace(/-/g, /) s2
javascript 如何 处理日期
var s1 = "2007-01-01";
var s2 = "2007-12-31";
s1 = s1.replace(/-/g, "/");
s2 = s2.replace(/-/g, "/");
s1 = new Date(s1);
s2 = new Date(s2);
var days= s1.getTime() - s2.getTime();
var time = parseInt(days / (1000 * 60 * 60 * 24));
alert("相差天数: " + days);
