删除数组中第i个以及i后j个元素
public class DeleteChar { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub char[] yourChar = new char[]{'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i'}; yourChar = DeleteChar.delete(yourChar, 2, 3); System.out.println(String.valueOf(yourChar));//输出为ab ghi } /* * 删除数组中从第i个元素以及后j个元素 * @input targetChar[] 目标数组 * @input i 第i个元素 * @input j 后j个元素 * @return 返回原来数据，其中i和i后的j个元素被' '代替，即被删除，清零成初始化状态 */ public static char[] delete(char[] targetChar, int i, int j) { char[] resultChar = new char[targetChar.length]; if (targetChar.length > 0 && i > 0 && j > 0 && i + j < targetChar.length) { for (int k = 0; k < targetChar.length; k++) { if (k < i || k > (j + i)) { resultChar[k] = targetChar[k]; } else { resultChar[k] = ' '; } } } else { System.out.println("Your input is wrong!"); System.exit(0); } return resultChar; }}