关于类的$this的有关问题

关于类的$this的问题

PHP code

class User {   private $uid;           private $fields;       public function __construct() {            $this->uid = null;            $this->fields = array(                            'username' => '',                            'password' => '',                            'emailAddr' => '',                            'isActive' => false,                            'permission' => 0                         );   }   public static function getById($user_id) {            $user = new User();                        $query = sprintf('SELECT username, password, email_addr, is_active, permission FROM %suser WHERE user_id = %d',                                DB_TBL_PREFIX, $user_id);            $result = mysql_query($query, $GLOBALS['DB']);            if (mysql_num_rows($result)) {                $row = mysql_fetch_assoc($result);                                $user->username = $row['username'];                $user->password = $row['password'];                $user->emailAddr = $row['email_addr'];                $user->isActive = $row['is_active'];                $user->permission = $row['permission'];                $user->uid = $user_id;            }            mysql_free_result($result);                        return $user;        }   }   public function save() {            if ($this->uid) {                $query = sprintf('UPDATE %suser SET username = "%s", password = "%s", email_addr = "%s",                                         is_active = %d, permission = %d WHERE user_id = %d',                                                        DB_TBL_PREFIX,                                                        mysql_real_escape_string($this->username, $GLOBALS['DB']),                                                        mysql_real_escape_string($this->password, $GLOBALS['DB']),                                                        mysql_real_escape_string($this->emailAddr, $GLOBALS['DB']),                                                        $this->isActive,                                                        $this->permission,                                                         $this->uid);                return mysql_query($query, $GLOBALS['DB']);            }            else {                $query = sprintf('INSERT INTO %suser(username, password, email_addr, is_active, permission)                                                                                 VALUES("%s", "%s", "%s", %d, %d)',                                                        DB_TBL_PREFIX,                                                        mysql_real_escape_string($this->username, $GLOBALS['DB']),                                                        mysql_real_escape_string($this->password, $GLOBALS['DB']),                                                        mysql_real_escape_string($this->emailAddr, $GLOBALS['DB']),                                                        $this->isActive,                                                        $this->permission);                if (mysql_query($query, $GLOBALS['DB'])) {                    $this->uid = mysql_insert_id($GLOBALS['DB']);                    return true;                }                else                    return false;            }        }

为什么save()中的
$query = sprintf('UPDATE %suser SET username = "%s", password = "%s", email_addr = "%s", 
is_active = %d, permission = %d WHERE user_id = %d',
DB_TBL_PREFIX,
mysql_real_escape_string($this->username, $GLOBALS['DB']),
mysql_real_escape_string($this->password, $GLOBALS['DB']),
mysql_real_escape_string($this->emailAddr, $GLOBALS['DB']),

$this->isActive,
$this->permission, 
$this->uid);
可以直接用$this调用permission？不是应该用$user调用$fields中的permission才对吗？



而getByID()中的
$user->username = $row['username'];
$user->password = $row['password'];
$user->emailAddr = $row['email_addr'];
$user->isActive = $row['is_active'];
$user->permission = $row['permission'];
$user->uid = $user_id;
也是这样，$user直接调用数组内的字段，为什么可以这样？

[解决办法]
我猜它定义了魔术方法__get和__set

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