c语言读取altair.txt文件
文本内容如下:
Feature: hypeworks version: 11.0 vendor: altair
start date: 2012-09-07 Expire date: 2012-09-20
30 of 100000 license used:
30 license used by root@aifserver[10.109.40.53]
login time: 2012-09-19 12:26 checkout time: 2012-09-19 11:26
这是文件的一段，还有许多相同格式的段落内容，我想用C语言逐行读取":"后边的内容，最好是用正则表达式去匹配
例如:定义一个char[256]="Feature: .*";通过定义这样的字符数组去匹配文档，如果有就分别读取"："后边的内容，还有就是读取 “30 of 100000 license used:”这段字符中的数值，还有“30 license used by root@aifserver[10.109.40.53]”这段字符中的@后边的aifserver和[10.109.40.53], 各位大侠帮帮忙吧，小弟C语言不是太懂，如果可以代码写的详细点，急！！！！
[解决办法]
//in.txt//Feature: hypeworks version: 11.0 vendor: altair//start date: 2012-09-07 Expire date: 2012-09-20#include <stdio.h>FILE *f;char ln[1000];char s[1000];int n;char *p;int L,k;int main() { f=fopen("in.txt","r"); if (NULL!=f) { n=0; while (1) { if (NULL==fgets(ln,1000,f)) break; n++; printf("Line %d\n",n); p=ln; while (1) { k=sscanf(p,"%*[^:]: %[^ \n]%n",s,&L); if (k==1) { printf(" the string after \': \' is [%s]\n",s); p+=L; } else if (k==-1) { break; } else { p++; } } } fclose(f); } return 0;}//Line 1// the string after ': ' is [hypeworks]// the string after ': ' is [11.0]// the string after ': ' is [altair]//Line 2// the string after ': ' is [2012-09-07]// the string after ': ' is [2012-09-20]