int compare( const void *arg1, const void *arg2 ) { /* Compare all of both st

int compare( const void *arg1, const void *arg2 ) { /* Compare all of both st
int compare( const void *arg1, const void *arg2 )
{
  /* Compare all of both strings: */
  return _stricmp(, * ( char** ) arg2 );
}


MSDN 上的一段程序

这里

 
* ( char** ) arg1


为什么要这样？跟（char*）arg1 有什么不同？？？

[解决办法]
不知，(char *)arg2 也可以编译通过的
等高手解释
[解决办法]
（char*）arg1 是把arg1当成char*
* ( char** ) arg1是把arg1当成char**，它传过去的是*arg1
[解决办法]

C/C++ code

/* QSORT.C: This program reads the command-line 
  * parameters and uses qsort to sort them. It 
  * then displays the sorted arguments. 
  */ 
  
 #include  <stdlib.h> 
 #include  <string.h> 
 #include  <stdio.h> 
  
 int compare( const void *arg1, const void *arg2 ); 
  
 void main( int argc, char **argv ) 
 { 
  int i; 
  /* Eliminate argv[0] from sort: */ 
  argv++; 
  argc--; 
  
  /* Sort remaining args using Quicksort algorithm: */ 
  qsort( (void *)argv, (size_t)argc, sizeof( char * ), compare ); 
  
  /* Output sorted list: */ 
  for( i = 0; i  < argc; ++i ) 
   printf( "%s ", argv[i] ); 
  printf( "\n" ); 
 } 
  
 int compare( const void *arg1, const void *arg2 ) 
 { 
  /* Compare all of both strings: */ 
  return _stricmp( * ( char** ) arg1, * ( char** ) arg2 ); 
 }