Dialog源码之语法学习括号直接判断即无if的判断
Dialog.java类里面，这个函数响应搜索的请求
/**
???? * This hook is called when the user signals the desire to start a search.
???? */
??? public boolean onSearchRequested() {
??????? final SearchManager searchManager = (SearchManager) mContext
??????????????? .getSystemService(Context.SEARCH_SERVICE);
??????? // can't start search without an associated activity (e.g a system dialog)
??????? if (!searchManager.hasIdent()) {
??????????? return false;
??????? }
??????? // associate search with owner activity if possible (otherwise it will default to
??????? // global search).
??????? final ComponentName appName = getAssociatedActivity();
??????? final boolean globalSearch = (appName == null);
??????? searchManager.startSearch(null, false, appName, null, globalSearch);
??????? dismiss();
??????? return true;
??? }
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红色的那句话对我来说比较新奇，是新的语法，我要学习；
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意思就是说：如果appName是null? 的话就返回true,否则就是false
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这函数的注释挺有意思，不和Activity关联的Dialog不能打开搜索，呵呵，看来验证了我的一个猜测，就是对话框的制造的种类。
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