Struts2练习--基于注解方式Action配置
还是已登录来说明下这个Action的配置，这里要说的Action的配置不是在src/struts.xml中，而是用注解方式来进行配置的
前提是除了基本的那六个jar包之外，还需要一个struts-2.1.8.1\lib\struts2-convention-plugin-2.1.8.1.jar
不过struts.xml还是要有的
具体示例
Login.jsp
?
<%@ page language="java" contentType="text/html; charset=UTF-8"
??? pageEncoding="UTF-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>login</title>
</head>
<body>
<form action="test/hello-world.action">
??????? 姓名:<input type="text" name="username"/><br>
???????? 密码:<input type="password" name="password"/><br>
???????? <input type="submit" value="登陆 ">
??? </form>
</body>
</html>
?
?
?
?src/struts.xml
?
<!DOCTYPE struts PUBLIC?
HelloWorldAction.java
?
package com.sspm.action.test;
import org.apache.struts2.convention.annotation.Action;
import org.apache.struts2.convention.annotation.ExceptionMapping;
import org.apache.struts2.convention.annotation.ExceptionMappings;
import org.apache.struts2.convention.annotation.InterceptorRef;
import org.apache.struts2.convention.annotation.InterceptorRefs;
import org.apache.struts2.convention.annotation.Namespace;
import org.apache.struts2.convention.annotation.ParentPackage;
import org.apache.struts2.convention.annotation.Result;
import org.apache.struts2.convention.annotation.Results;
import com.opensymphony.xwork2.ActionSupport;
/**
?* Struts2基于注解的Action配置
?* @author wangpj
?*
?*/
@ParentPackage("struts-default")
@Namespace("/test")
//@Namespace("")
@Results(
?? {
?? @Result(name="success",location="/jsp/ok.jsp"),
?? @Result(name="error",location="/jsp/errors.jsp")
?? }
)
@ExceptionMappings(
??{
???@ExceptionMapping(exception="java.lange.Exception",result="error")
??}
)
@InterceptorRefs({
?@InterceptorRef("defaultStack")
})
public class HelloWorldAction extends ActionSupport {
?private static final long serialVersionUID = 1L;
?
?private String username;
?private String password;
?
?//或者写成? @Action(value = "login")
?//请求url: http://localhost:8080/sshtest/test/login!login.action
?//请求其他方法: http://localhost:8080/sshtest/test/login!add.action
?// 跳转页 走的是全部Result
?@Action("login")
?public String login() throws Exception{
??System.out.println("===========");
???????? return SUCCESS;
?}
?
?//有“/” 命名空间被替换
?//请求url: http://localhost:8080/sshtest/other/add!add.action
?//请求其他方法???? http://localhost:8080/sshtest/other/add!login.action
?// 跳转页 走的是局部Result
?@Action(value="/other/add",results = { @Result(name = "success", location = "/index.jsp")})
?public String add() throws Exception{
??System.out.println("add>>>>>>");
??return SUCCESS;
?}
?//默认请求action类，去掉结尾"Action"，然后按照驼峰规则添加“-”,字符全部小写
?//请求url: http://localhost:8080/sshtest/test/hello-world.action?username=abc&password=123
?@Override
?public String execute() throws Exception {
??//条件password.equals("123") 时 password为null时抛出异常 转向error
??if ("abc".equals(username)&&"123".equals(password)) {
???System.out.println("abc>>>>>>");
????? return SUCCESS;
???? } else {
????? System.out.println("other>>>>>>");
????? return ERROR;
???? }
?}
?public String getUsername() {
??return username;
?}
?public void setUsername(String username) {
??this.username = username;
?}
?public String getPassword() {
??return password;
?}
?public void setPassword(String password) {
??this.password = password;
?}
?
}
ok.jsp和errors.jsp我就不贴出来了
?
注解配置的解释
?
??1) @ParentPackage 指定父包
??2) @Namespace 指定命名空间
??3) @Results 一组结果的数组
??4) @Result(name="success",location="/msg.jsp") 一个结果的映射
??5) @Action(value="login") 指定某个请求处理方法的请求URL。注意，它不能添加在Action类上，要添加到方法上。
??6) @ExceptionMappings 一级声明异常的数组
??7) @ExceptionMapping 映射一个声明异常
? 8) @InterceptorRefs 拦截器
