SQL2005 对字段进行拆分
这样才可以把
某一个字段 字符拆分成 多个字段如
准备拆分的
拆分后的
希望有人回答 谢谢了 真心谢谢
[解决办法]
declare @str varchar(100)set @str='0000zt0000 5842001314 0000zt0000@163.com'select name1, email, reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em, replace(replace(@str,name1+' ',''),' '+email,'') passfrom( select substring(@str,0,charindex(' ',@str)) name1, reverse(substring(reverse(@str),0,charindex(' ',reverse(@str)))) email)t
[解决办法]
create table #urTable([str] varchar(1000))insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'select name1, email, reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em, replace(replace([str],name1+' ',''),' '+email,'') pass from( select substring([str],0,charindex(' ',[str])) name1, reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable)t/*name1 email em pass----------------------------------------------------------------0000zt0000 0000zt0000@163.com @163.com 5842001314(1 行受影响)*/
[解决办法]
create table #urTable([str] varchar(1000))
insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'
select name1,
email,
reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em,
replace(replace([str],name1+' ',''),' '+email,'') pass from
(
select substring([str],0,charindex(' ',[str])) name1,
reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable
)t
[解决办法]
create table #urTable([str] varchar(1000))insert into #urTable select '0000zt0000 5842001314 0000zt0000@163.com'select name1, email, reverse(substring(reverse(email),1,charindex('@',reverse(email)))) em, replace(replace([str],name1+' ',''),' '+email,'') pass from( select substring([str],0,charindex(' ',[str])) name1, reverse(substring(reverse([str]),0,charindex(' ',reverse([str])))) email,[str] from #urTable)t
[解决办法]