C++新手求教，还望各位老师多多指点！解决方法

C++新手求教，还望各位老师多多指点！
char the_Exit;
cout << "Are you sure eixt? y/n";
cin >> the_Exit;
if (the_Exit == n)
break;
else
continue;
我想通过这段程序来实现退出功能。为什么会报错呢？如何才能完成输入y/n退出呢？

[解决办法]

C/C++ code

#include <iostream>using namespace std;int main(){    char the_Exit;        char y = 'n';    while (true)    {        cout << "Are you sure eixt? y/n  \n";        cin >> the_Exit;        if (the_Exit == y)            break;        else            continue;    }}
[解决办法]
#include <iostream>

using namespace std;

int main()
{


char the_Exit;

char y = 'n';
while (true)
{
cout << "Are you sure eixt? y/n  \n";
cin >> the_Exit;

if (the_Exit == y)
continue;
else
break;
}

}
[解决办法]
你的变量类型好乱啊，编译器没有报错?再设一个整型变量吧。还有按你写的，continue语句也没什么意义，不用写。下面是我写的，Visual c++ 6.0 通过了，楼主参考一下。
#include <iostream>
int main()
{
  using namespace std;
  char the_Exit; 
  char y,n;
  int Exit;
  while (true)
  {
  cout << "Are you sure eixt? y/n"<<endl;
  cin >> the_Exit;

  if (the_Exit=='y')
 Exit=0;
  else
 Exit = 1;

  if (Exit==0)
 break;
  }
  return 0;
}

最好用下面这个，很简洁
#include <iostream>
using namespace std;  
int main()
{  
  char the_Exit;
  char y,n;
  while (true)
  {
  cout << "Are you sure eixt? y/n"<<endl;
  cin >> the_Exit;

  if (the_Exit=='y')
 break;
  }
  return 0;
}