如何用xsl转xml文件，java代码怎么写
现在有一个cdcatalog.xml文件，
<?xml version="1.0" encoding="ISO-8859-1"?>
<catalog>
<cd>
<title>Empire Burlesque</title>
<artist>Bob Dylan</artist>
<country>USA</country>
<company>Columbia</company>
<price>10.90</price>
<year>1985</year>
</cd>
<cd>
<title>Fmpire Burlesque</title>
<artist>FBob Dylan</artist>
<country>FUSA</country>
<company>FColumbia</company>
<price>20.90</price>
<year>2005</year>
</cd>
</catalog>
和一个cdcatalog.xsl文件，内容如下：
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<h2>My CD Collection</h2>
<table border="1">
<tr bgcolor="#9acd32">
<th align="left">Title</th>
<th align="left">Artist</th>
</tr>
<xsl:for-each select="catalog/cd">
<tr>
<td><xsl:value-of select="title"/></td>
<td><xsl:value-of select="artist"/></td>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
想把转换后的结果输出到result.xml文件中，
请问java代码应该怎么写？
[解决办法]
public static void main(String[] args) { String xmlFileName = "d:/cdcatalog.xml"; String xslFileName = "d:/cdcatalog.xsl"; String htmlFileName = "d:/out.xml"; transform(xmlFileName, xslFileName, htmlFileName); } public static void transform(String xmlFileName, String xslFileName, String htmlFileName) { try { TransformerFactory tFac = TransformerFactory.newInstance(); Source xslSource = new StreamSource(xslFileName); Transformer t = tFac.newTransformer(xslSource); File xmlFile = new File(xmlFileName); File htmlFile = new File(htmlFileName); Source source = new StreamSource(xmlFile); Result result = new StreamResult(htmlFile); t.transform(source, result); } catch (TransformerConfigurationException e) { e.printStackTrace(); } catch (TransformerException e) { e.printStackTrace(); } }