c++的两个题目
1、继承与派生类的应用
（１）定义一个日期（年、月、日）的类和一个时间（时、分、秒）的类，并由这两个类派生出日期和时间类。要求在主函数中完成基类和派生类的测试工作。
2、运算符重载的基本设计
（１）定义一个复数类，通过重载运算符：“*、/”，直接实现二个复数之间的乘除运算。
编写一个完整的程序，测试重载运算符的正确性。要求乘法“*”用友元函数实现重载，除法“/”用成员函数实现重载。
谁能把这两个题目解答一下呢？
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自己做吧 一些简单的作业题 都不想做了
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//function Data.h#ifndef DATA_H#define DATA_Hclass Data{public: Data( int = 1,int = 1,int = 1900 ); void setMonth( int ); void setDay( int ); void setYear( int ); void nextDay(); int getMonth() const; int getDay() const; int getYear() const; void displayDate() const; int checkDay( int );private: int month; int day; int year; };#endif//time.h#ifndef TIME_H#define TIME_H#include<iostream>using namespace std;class Time{public: Time( int = 0,int = 0 ,int = 0 ); void setTime( int ,int ,int ); void setHour( int ); void setMinute( int ); void setSecond( int ); int getHour(); int getMinute(); int getSecond(); void printMilitary(); void printStandard(); void tick();private: int hour; int minute; int second;};#endif#ifndef DT_H#define DT_H#include "data.h"#include "time.h"class DT : public Time, public Data{public: DT(int m = 1,int d = 1,int y = 1900,int hr = 0,int min = 0,int sec = 0 ): Time(hr,min,sec),Data(m,d,y) {} void printMilitary(); void printStandard(); void tick();};#endif //function Data.cpp#include <iostream>using namespace std;#include "data.h"Data::Data( int m,int d,int y){ month = 1; day =1; year = 1900; setMonth( m ); setDay( d ); setYear( y );}void Data::setMonth( int m ){ if( m < 1 || m > 12 ) { //cout<<"ERROR! enter wrong Month!"<<endl; month = 1; return ; } else month = m;}void Data::setDay( int d ){ if( d < 1 || d > 31 ) { //cout<<"ERROR! enter wrong Month!"<<endl; day = 1; return ; } else day = checkDay( d );}void Data::setYear( int y ){ if( y < 1900 || y > 2010 ) { //cout<<"ERROR! enter wrong Month!"<<endl; year = 1900; return ; } else year = y;}int Data::getMonth() const{ return month;}int Data::getDay() const{ return day;}int Data::getYear() const{ return year;}void Data::displayDate() const{ cout<<"Date is: "<<getMonth()<<"/"<<getDay()<<"/"<<getYear()<<endl;}int Data::checkDay( int d){ static int daysPerMonth[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31}; if( month != 2 ) { if( d > daysPerMonth[month] || d < 0 ) { //cout<<"ERROR! enter day wrong!"<<endl; return 1; } else return d; } else { int days; days = ( year % 400 == 0 || (year % 4 == 0 && year % 100 != 0) ? 29 : 28); if( d > 0 && d <= days ) return d; else { //cout<<"ERROR! enter day wrong!"<<endl; return 1; } } return 1;}void Data::nextDay(){ setDay( getDay() + 1 ); if( getDay() == 1 ) { setMonth( getMonth() + 1 ); if( getMonth() == 1 ) setYear( getYear() +1 ); }}//function time.cpp#include<iostream>using namespace std;#include"time.h"Time::Time(int hr,int min,int sec){ hour=( hr >= 0 && hr < 24 ) ? hr : 0; minute=( min >= 0 && min < 60 ) ? min : 0; second=( sec >= 0 && sec < 60 ) ? sec : 0;}void Time::setTime(int h,int m,int s){ hour = ( h >= 0 && h<24 ) ? h : 0; minute = ( m >= 0 && m < 60 ) ? m : 0; second = ( s >= 0 && s < 60 ) ? s : 0;}void Time::setHour(int h){ hour = ( h >= 0 && h < 24 ) ? h : 0;}void Time::setMinute(int m){ minute = ( m >= 0 && m < 60 ) ? m : 0;}void Time::setSecond(int s){ second = ( s >= 0 && s < 60 ) ? s : 0;}int Time::getHour(){ return hour;}int Time::getMinute(){ return minute;}int Time::getSecond(){ return second;}void Time::printMilitary(){ cout << ( hour < 10 ? "0" : "" )<< hour << ":" << ( minute < 10 ? "0" : "" ) << minute << ":" << ( second < 10 ? "0" : "" ) << second;}void Time::printStandard(){ cout << ( ( hour == 0 || hour == 12 ) ? 12 : hour % 12 ) << ":" << ( minute < 10 ? "0" : "" ) << minute << ":" << ( second < 10 ? "0" : "" ) << second << ( hour < 12 ? "AM" : "PM" );}void Time::tick(){ setSecond( ( getSecond() + 1 ) % 60 ); if ( getSecond() == 0 ) { setMinute( ( getMinute() + 1 ) % 60 ); if ( getMinute() == 0 ) setHour( ( getHour() + 1 ) % 24 ); }}#include "dt.h"#include <iostream>using namespace std;void DT::printMilitary(){ cout<<(getHour()<10?"0":"")<<getHour()<<" : " <<(getMinute()<10?"0":"")<<getMinute()<<" : " <<(getSecond()<10?"0":"")<<getSecond()<<" : " <<getMonth()<<"/" <<getDay()<<"/" <<getYear()<<endl;}void DT::printStandard(){ cout<<((getHour()==0||getHour()==12)?12:getHour()%12)<<" : " <<(getMinute()<10?"0":"")<<getMinute()<<" : " <<(getSecond()<10?"0":"")<<getSecond()<<" " <<(getHour()<12?"AM":"PM")<<" " <<getMonth()<<"/"<<getDay()<<"/"<<getYear()<<endl;}void DT::tick(){ setSecond( ( getSecond() + 1 ) % 60 ); if ( getSecond() == 0 ) { setMinute( ( getMinute() + 1 ) % 60 ); if ( getMinute() == 0 ) { setHour( ( getHour() + 1 ) % 24 ); if( getHour() == 0 ) nextDay(); } }}#include "dt.h"#include <iostream>using namespace std;int main(){ DT dataandtime; dataandtime.printMilitary(); return 0;}
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/* 假设你已经知道了 复数的数学性质 */#include <iostream>using namespace std;class Complex { double re, im;public: Complex(): re(0), im(0) {} Complex(double r): re(r), im(0) {} Complex(double r, double i): re(r), im(i) {} friend Complex operator*(Complex, Complex); Complex operator/(Complex); void display(void) { cout << re<<"+"<<im<<"i"<<endl; }};Complex operator *(Complex c1, Complex c2){ Complex ret; ret.re = c1.re*c2.re - c1.im*c2.im; ret.im = c1.re*c2.im + c1.im*c2.re; return ret;}Complex Complex::operator/(Complex c){ Complex ret; double z = c.re*c.re + c.im*c.im; /* z != 0*/ ret.re = (re*c.re + im*c.im)/z; ret.im = (im*c.re - re*c.im)/z; return ret;}int main(){ Complex c1(2, 3), c2(1, 4); Complex c3 = c1/c3; c3.display(); return 0;}
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不好意思 那里是 c3 = c1/c2;
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这是第二题
#include <iostream>using namespace std;class Complex{public: Complex():re(0),im(0){} Complex(double r,double i):re(r),im(i){} friend Complex operator*(Complex&,Complex&); Complex operator/(Complex&); void display(void) { cout<<"("<<re<<","<<im<<")"<<endl; }private: double re; double im;};Complex Complex::operator /(Complex& c1){ Complex c2; double d; d = c1.re * c1.re + c1.im * c1.im; c2.re = (c1.re * re + c1.im * im) / d; c2.im = (c1.im * re - c1.re * im) / d; return c2;}Complex operator* (Complex& c1,Complex& c2){ Complex c3; c3.re = c1.re * c2.re - c1.im * c2.im; c3.im = c1.re * c2.im + c1.im * c2.re; return c3; }void main(){ Complex a(1,2),b(2,4),c,d; c = a * b; d = b / a; c.display(); d.display();}
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