android异常处理发送消息给服务器
?
转自：http://www.cnblogs.com/stay/archive/2011/07/21/2113167.html
程序员最头疼的事情就是bug和debug。这次debug长达20天，搞的我心力交瘁。累，因为Android兼容性，不同手机会有不同的bug出来，而且很难复现，所以就上网找了下类似保存错误log到文件再上传到服务器，现把源码也共享出来。上传至服务器的代码我没加。相信大家都有现成的代码了。
先讲下原理，跟JavaEE的自定义异常捕获一样，将错误一直向上抛，然后在最上层统一处理。这里就可以获得Exception Message，进行保存操作
异常捕获类如下：
//??????????????? 可以只创建一个文件，以后全部往里面append然后发送，这样就会有重复的信息，个人不推荐 ????????????????String fileName = "crash-" + System.currentTimeMillis()? + ".log";?? ????????????????File file = new File(Environment.getExternalStorageDirectory(), fileName); ????????????????try { ????????????????????FileOutputStream fos = new FileOutputStream(file,true); ????????????????????fos.write(message.getBytes()); ????????????????????for (int i = 0; i < stack.length; i++) { ????????????????????????fos.write(stack[i].toString().getBytes()); ????????????????????} ????????????????????fos.flush(); ????????????????????fos.close(); ????????????????} catch (Exception e) { ????????????????} ????????????????Looper.loop();?? ????????????}?? ????????????}.start();?? ????????return false;?? ????}?? ????????// TODO 使用HTTP Post 发送错误报告到服务器? 这里不再赘述 //??? private void postReport(File file) {?? //????? 在上传的时候还可以将该app的version，该手机的机型等信息一并发送的服务器， //????? Android的兼容性众所周知，所以可能错误不是每个手机都会报错，还是有针对性的去debug比较好 //??? }?? }??在Application onCreate时就注册ExceptionHandler，此后只要程序在抛异常后就能捕获到。
view sourceprint?public class App extends Application{ ????????@Override??????????public void onCreate() {?? ????????????super.onCreate();?? ????????????CrashHandler crashHandler = CrashHandler.getInstance();?? ????????????//注册crashHandler?? ????????????crashHandler.init(getApplicationContext());?? ????????}?? }view sourceprint?public class LogActivity extends Activity { ????@Override????public void onCreate(Bundle savedInstanceState) { ????????super.onCreate(savedInstanceState); ????????setContentView(R.layout.main); ????????try {//制造bug ????????????File file = new File(Environment.getExternalStorageState() ,"crash.bin"); ????????????FileInputStream fis = new FileInputStream(file); ????????????byte[] buffer = new byte[1024]; ????????????fis.read(buffer); ????????} catch (Exception e) { ????????????//这里不能再向上抛异常，如果想要将log信息保存起来，则抛出runtime异常， //????????? 让自定义的handler来捕获，统一将文件保存起来上传 ????????????throw new RuntimeException(e); ????????} ????} }注意，如果catch后不throw就默认是自己处理了，ExceptionHandler不会捕获异常了。
再分享一个Log的封装类，只要在这里设置DEBUG的值就能让控制台是否打印出log
view sourceprint?public class DebugUtil { ????public static final String TAG = "ICON"; ????public static final boolean DEBUG = true; ??????????public static void toast(Context context,String content){ ????????Toast.makeText(context, content, Toast.LENGTH_SHORT).show(); ????} ??????????public static void debug(String tag,String msg){ ????????if (DEBUG) { ????????????Log.d(tag, msg); ????????} ????} ??????????public static void debug(String msg){ ????????if (DEBUG) { ????????????Log.d(TAG, msg); ????????} ????} ??????????public static void error(String tag,String error){ ????????Log.e(tag, error); ????} ??????????public static void error(String error){ ????????Log.e(TAG, error); ????} }