nyoj 可以直接写的简单题
Triangular Sums nyoj 122
#include<iostream>using namespace std;int main(){ int N, score; cin>>N; while(N--) { cin>>score; if(score >= 90 && score <= 100) cout<<"A"<<endl; else if(score >= 80 && score <= 89) cout<<"B"<<endl; else if(score >= 70 && score <= 79) cout<<"C"<<endl; else if(score >= 60 && score <= 69) cout<<"D"<<endl; else if(score >= 0 && score <= 59) cout<<"E"<<endl; } return 0;}