一路字符串题

一道字符串题
wsprintf中有三个参数，前两个为buffer和format,现在给出了buffer和format,其中format只含有“%s”这一种格式,问，怎样输出每一个%s所代表的字符串。例如buffer为“abcdab1234", format为"%sab%s34"，那么输出的子字符串应为“abcd”，“12”。

[解决办法]

C/C++ code

// strstr.cpp : Defines the entry point for the console application.//#include "stdafx.h"#include "memory.h"#include "string.h"int main(int argc, char* argv[]){    char ori[] = "abcdab1234";    char format[] = "%sab%s34";    char *p = format;    char tmp[ 4 ][ 10 ];    int count;    int len;    int i;    memset( tmp, 0, sizeof( tmp ) );    count = 0;    len = 0;    while( *p )    {        if( '%' == *p )        {            if( p != format )            {                count++;            }            len = 0;            tmp[ count ][ len++ ] = '%';            p++;            tmp[ count ][ len++ ] = *p;            len = 0;            count++;        }        else        {            tmp[ count ][ len++ ] = *p;        }        p++;    }    count++;    for( i = 0; i < count; i++ )    {        printf( "format part %d is     --- %s \r\n", i + 1, tmp[ i ] );    }    char *q = ori;    for( i = 0; i < count; i++ )    {        if( !strcmp( tmp[ i ], "%s" ) )        {            char *t = strstr( q + 1, tmp[ i + 1 ] );            char dest[ 0x10 ] = "";            memcpy( dest, q, ( int )( t - q ) );            printf( "the %%s is %s \r\n", dest );            q += strlen( dest );            q += strlen( tmp[ i + 1 ] );        }    }    return 0;}