数据库字段存的是多个用户的ID，取出来是多个用户的姓名
select wm_concat(t.user_name) username from bos_t_user t where t.user_id in (with tab as (select '990000000000000001,990000000000000002,990000000000000003' id from ZL_T_PROJECT where project_id = 990000000000000005) select substr(',' || id || ',', instr(',' || id || ',', ',', 1, level) + 1, instr(',' || id || ',', ',', 1, level + 1) - instr(',' || id || ',', ',', 1, level) - 1) newid from tab connect by level <= length(',' || id || ',') - length(replace(',' || id || ',', ',', '')) - 1 )?