依照结构体中的2个关键变量排序

按照结构体中的2个关键变量排序。
typedef struct __tree_node
{
  int no;
  double height;
  int age;
  int level;
  char name[12];
  char addr[64]; 
} tree_node;

需要排序一组这样的结构体，从大到小，age最大的在最前面，如果age相同就按照height来从大到小排序。
有现成的算法来排序么？


[解决办法]
自己写一个比较大小的函数吧

C/C++ code

int less(const tree_node *p1, const tree_node *p2){    if (p1->age < p2-> age)    {        return 1;    }    if (p1->age == p2->age && p1->height < p2->height)    {        return 1;    }    return 0;}
[解决办法]
重载一下比较大小的< > = 的运算符
然后用 C++标准库里提供的sort
例子如下：
// sort algorithm example
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;

bool myfunction (int i,int j) { return (i<j); }

struct myclass {
 bool operator() (int i,int j) { return (i<j);}
} myobject;

int main () {
 int myints[] = {32,71,12,45,26,80,53,33};
 vector<int> myvector (myints, myints+8);               // 32 71 12 45 26 80 53 33
 vector<int>::iterator it;

 // using default comparison (operator <):
 sort (myvector.begin(), myvector.begin()+4);           //(12 32 45 71)26 80 53 33

 // using function as comp
 sort (myvector.begin()+4, myvector.end(), myfunction); // 12 32 45 71(26 33 53 80)

 // using object as comp
 sort (myvector.begin(), myvector.end(), myobject);     //(12 26 32 33 45 53 71 80)

 // print out content:
 cout << "myvector contains:";
 for (it=myvector.begin(); it!=myvector.end(); ++it)
   cout << " " << *it;

 cout << endl;

 return 0;
}
[解决办法]
C/C++ code
#include<iostream>#include<vector>#include<algorithm>using namespace std;typedef struct __tree_node{  int no;  double height;  int age;  int level;  char name[12];  char addr[64];} tree_node;inline bool operator > (const tree_node& n1,const tree_node& n2) {    if(&n1 != &n2) {        if(n1.age > n2.age) {            return true;        } else if(n1.age == n2.age ) {            if(n1.height > n2.height)                return true;            else                return false;        } else {            return false;        }    }    return false;}inline bool operator < (const tree_node& n1, const tree_node& n2) {    return !(n1 > n2);}bool mysort(const tree_node& n1,const tree_node& n2) {    return n1 > n2;}int main(void) {    vector<tree_node> v;    tree_node n1 = {1,3.4,8,3,"abc","dd"};    tree_node n2 = {1,3.4,28,3,"abc","ee"};    v.push_back(n1);    v.push_back(n2);    for(vector<tree_node>::iterator it = v.begin(); it != v.end(); it++) {        cout<<"age is "<<it->age<<"\t height is "<<it->height<<endl;    }    sort(v.begin(),v.end(),mysort);    for(vector<tree_node>::iterator it = v.begin(); it != v.end(); it++) {            cout<<"age is "<<it->age<<"\t height is "<<it->height<<endl;    }    return 0;}