C# 自定义网络协议的问题,怎样写协议才可以使发送byte[]数组到服务端后服务端可以轻松解析成键值对形式,或者说怎样写既方便传输又方便解析
我自定义一个协议,但是遇到了一个问题,服务端要解析客户端发送过来协议数据,很不方便,协议格式如下
/// <summary>/// 基础协议/// </summary>/// <param name="name">协议名称</param>/// <param name="command">命令类型[枚举]</param>/// <param name="protocol">网络协议类型[枚举]</param>/// <param name="packageBody">消息包体</param>/// <param name="isNeedReturn">是否需要回馈[枚举]</param>/// <param name="isNeedEncrypt">是否加密[枚举]</param>/// <param name="sessionCode">会话码</param>/// <returns></returns>public static byte[] GetProtocol(String name, int command, int protocol, byte[] packageBody, Return isNeedReturn, Encrypt isNeedEncrypt, String sessionCode){ byte[] p1 = Encoding.Default.GetBytes(name); byte[] p2 = Encoding.Default.GetBytes(command.ToString()); byte[] p3 = Encoding.Default.GetBytes(protocol.ToString()); byte[] p4 = packageBody; byte[] p5 = Encoding.Default.GetBytes(isNeedReturn.ToString()); byte[] p6 = Encoding.Default.GetBytes(isNeedEncrypt.ToString()); //这里我把decollator作为的一个分隔符 byte[] decollator = Encoding.Default.GetBytes("≮?≯"); byte[] result = new byte[p1.Length + p2.Length + p3.Length + p4.Length + p5.Length + p6.Length]; Array.Copy(p1, 0, result, 0, p1.Length); Array.Copy(decollator, 0, result, p1.Length, decollator.Length); Array.Copy(p2, 0, result, p1.Length + decollator.Length, p2.Length); Array.Copy(decollator, 0, result, p1.Length + p2.Length + decollator.Length, decollator.Length); Array.Copy(p3, 0, result, p1.Length + p2.Length + decollator.Length * 2, p3.Length); Array.Copy(decollator, 0, result, p1.Length + p2.Length + p3.Length + decollator.Length * 2, decollator.Length); Array.Copy(p4, 0, result, p1.Length + p2.Length + p3.Length + decollator.Length * 3, p4.Length); Array.Copy(decollator, 0, result, p1.Length + p2.Length + p3.Length + p4.Length + decollator.Length * 3, decollator.Length); Array.Copy(p5, 0, result, p1.Length + p2.Length + p3.Length + p4.Length + decollator.Length * 4, p5.Length); Array.Copy(decollator, 0, result, p1.Length + p2.Length + p3.Length + p4.Length + p5.Length + decollator.Length * 4, decollator.Length); Array.Copy(p6, 0, result, p1.Length + p2.Length + p3.Length + p4.Length + p5.Length + decollator.Length * 5, p6.Length); return result;}
static void Main(string[] args) { Dictionary<string, string> dics = new Dictionary<string, string>(); dics.Add("username", "007"); dics.Add("password", "@#$"); Socket socket = new Socket(AddressFamily.InterNetwork, SocketType.Stream, ProtocolType.Tcp); socket.Connect(new IPEndPoint(IPAddress.Parse("127.0.0.1"), 1000)); JavaScriptSerializer jss = new JavaScriptSerializer(); string s = jss.Serialize(dics); socket.Send(Encoding.UTF8.GetBytes(s.ToString())); socket.Close(); }
[解决办法]
证明json之类的协议的性能要比xml等不快很多倍 --> 证明json之类的协议的性能要比xml等不知快了很多倍
json比xml快很多倍。现在的计算机非常快,使用json传送命令是非常合适的。用不着搞一大堆“啊~~~~呀~~~~咿咿呀呀~~~~~”的莫名其妙的二进制格式,然后你自己再写一大堆缓慢的所谓解析。
[解决办法]
这不叫“自定义网络协议的问题”,这叫“自定义数据传输结构”。
1、序列和反序列
2、json
3、xml