怎样在C语言中动态显示时间,该怎么处理

怎样在C语言中动态显示时间
这是一个显示电脑当前时间的程序，怎么能让它“动”起来呢？即不断刷新，像电子手表一样显示最新时间.
#include <stdio.h> 
#include <string.h> 
#include <time.h> 

int Show(void) 
{ 
  char str[100]; 
  time_t t; 
  struct tm *lt; 
  t = time(NULL); 
  lt = localtime(&t); 
  strftime(str,100,"%Y-%m-%d %H:%M:%S ",lt); 
  printf("当前日期及时间是:\n%s\n",str); 
  getch(); 
  return 0; 
} 

main()
{
Show();
}

[解决办法]

C/C++ code

#include <stdio.h> #include <string.h> #include <time.h> #include <stdlib.h>int Show(void) {   char str[100];   time_t t;   struct tm *lt;   t = time(NULL);   lt = localtime(&t);   strftime(str,100,"%Y-%m-%d  %H:%M:%S ",lt);   printf("当前日期及时间是:\n%s\n",str);    return 0; } void sleep( clock_t wait ){   clock_t goal;   goal = wait + clock();   while( goal > clock() )      ;}main() {         while(true)    {    system("cls");    Show();    sleep(1000);    }}
[解决办法]
C/C++ code
 
 /********************************************  
 **  
 **    Windows XP sp2, Micrsoft Visual C++ 6.0  
 **    myDate.c  
 **  
 **********************************************/  
  
  
 #include  <stdio.h>  
 #include  <stdlib.h>  
 #include  <time.h>  
  
 #include  <windows.h>  
  
 typedef struct  
 {  
    int year;  
    int month;  
    int day;  
    int hour;  
    int minute;  
    int second;  
    int week;  
 }myDate;  
  
 int leap(int year)  
 {  
    if (year%4 == 0 && year%100 !=0 || year%400 == 0)  
    {  
     return 1;  
    }  
    return 0;  
 }  
  
 int main()  
 {  
    int days[13] = {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31};  
    char * weekday[] = {"星期日", "星期一", "星期二", "星期三", "星期四", "星期五", "星期六"};  
    time_t t = time(NULL);  
    struct tm *cur = localtime(&t);  
  
    myDate Date = {cur->tm_year+1900, cur->tm_mon + 1, cur->tm_mday, cur->tm_hour, cur->tm_min, cur->tm_sec, cur->tm_wday};  
  
    printf("%4d年%02d月%02d日[%s]%02d时%02d分%02d秒\r", Date.year, Date.month, Date.day, weekday[Date.week], Date.hour, Date.minute, Date.second);  
  
    while(1)  
    {  
       Sleep(1000);  
       days[2] = (leap(Date.year) ? 28:29);  
  
       Date.second++;  
       if ( Date.second == 60)  
       {  
         Date.second = 0;  
         Date.minute++;  
  
       }  
  
       if (Date.minute == 60)  
       {  
         Date.minute = 0;  
         Date.hour++;  
       }  
  
       if (Date.hour == 24)  
       {  
         Date.hour = 0;  
         Date.week = (++Date.week)%7;  
         Date.day++;  
       }  
  
  
       if (Date.day == (days[Date.month] + 1))   
 
       {  
          Date.day = 1;  
          Date.month++;  
       }  
  
       if (Date.month == 13)  
       {  
          Date.month = 1;  
          Date.year++;  
       }  
  
       printf("%4d年%02d月%02d日[%s]%02d时%02d分%02d秒\r", Date.year, Date.month, Date.day, weekday[Date.week], Date.hour, Date.minute, Date.second);  
    }  
  
    return 0;  
 } 
  
  
 

[解决办法]
C/C++ code
#include <time.h>#include <stdio.h>int main(){ time_t lt; for(;!kbhit();) {  lt=time(NULL);  printf(ctime(&lt));  delay(10000);  clrscr();  }  return 0; }
[解决办法]
C/C++ code
#include <time.h>int main(){time_t t; struct tm *lt; for(;!kbhit();) {time(&t);  lt=localtime(&t);  printf("%d-%d-%d\n",1900+lt->tm_year,lt->tm_mon,lt->tm_mday);  printf("%d.%d.%d",lt->tm_hour,lt->tm_min,lt->tm_sec);  delay(10000);  system("cls"); } return 0;}