java输出4位网站验证码, 在线等
java文件中，需输出 4位网站验证码 要求：
1 不能重复
2 数字和大小写字符, 但是不能包含1,0,o,O,l,L,Z,2,9,g等
这如何实现呀，thanks
[解决办法]
到百度上去找，这样的例子大一堆
[解决办法]
最笨的方法是：把能用的数字和字母放入数组，写个四重循环就ok了。
不知道lz说的不能重复是每一位不能重复还是生成出来的四位码之间不能重复，这种例子很多的。
[解决办法]
- Java code
private static final String AUTH_CODE = "0123456789"; public static String getCheckCode() { StringBuilder sb = new StringBuilder(); for(int i = 0;i<4;i++) { int index = new Random().nextInt(AUTH_CODE.length()); sb.append(AUTH_CODE.charAt(index)); } return sb.toString(); }
[解决办法]
1、如下是产生验证码的class，你只需要小小改一下，排除1,0,o,O,l,L,Z,2,9,g等。
- Java code
import java.awt.Graphics;import java.awt.image.BufferedImage;import java.util.Random;//定义类public class VerifyCode { static Random r = new Random(); static String ssource = "0123456789"; static char[] src = ssource.toCharArray(); //产生随机字符串 private static String randString (int length){ char[] buf = new char[length]; int rnd; for(int i=0;i<length;i++){ rnd = Math.abs(r.nextInt()) % src.length; buf[i] = src[rnd]; } return new String(buf); } //调用该方法，产生随机字符串, //参数i: 为字符串的长度 public String runVerifyCode(int i){ String VerifyCode = randString(i); return VerifyCode; } //给定范围获得随机颜色 public Color getRandColor(int fc,int bc) { Random random = new Random(); if(fc>255) fc=255; if(bc>255) bc=255; int r=fc+random.nextInt(bc-fc); int g=fc+random.nextInt(bc-fc); int b=fc+random.nextInt(bc-fc); return new Color(r,g,b); } //调用该方法将得到的验证码生成图象 //sCode:传递验证码 w:图象宽度 h:图象高度 public BufferedImage CreateImage(String sCode) { try{ //字符的字体 Font CodeFont = new Font("Arial Black",Font.PLAIN,16); int iLength = sCode.length(); //得到验证码长度 int width=22*iLength, height=20; //图象宽度与高度 int CharWidth = (int)(width-24)/iLength; //字符距左边宽度 int CharHeight = 16; //字符距上边高度 // 在内存中创建图象 BufferedImage image = new BufferedImage(width,height,BufferedImage.TYPE_INT_RGB); // 获取图形上下文 Graphics g = image.getGraphics(); //生成随机类 Random random = new Random(); // 设定背景色 g.setColor(getRandColor(200,240)); g.fillRect(0, 0, width, height); //设定字体 g.setFont(CodeFont); //画随机颜色的边框 g.setColor(getRandColor(10,50)); g.drawRect(0,0,width-1,height-1); // 随机产生155条干扰线，使图象中的认证码不易被其它程序探测到 g.setColor(getRandColor(160,200)); for (int i=0;i<155;i++) { int x = random.nextInt(width); int y = random.nextInt(height); int xl = random.nextInt(12); int yl = random.nextInt(12); g.drawLine(x,y,x+xl,y+yl); } for (int i=0;i<iLength;i++) { String rand = sCode.substring(i,i+1); // 将认证码显示到图象中 g.setColor(new Color(20+random.nextInt(60),20+random.nextInt(120),20+random.nextInt(180))); g.drawString(rand,CharWidth*i+14,CharHeight); } // 图象生效 g.dispose(); return image; }catch(Exception e){ //e.printStackTrace(); //System.out.println(e.getMessage()); } return null; } //测试 public static void main(String[] args){ //VerifyCode vc = new VerifyCode(); //String s1 = vc.runVerifyCode(4); //Fun.DreamNewsTitle;System.out.println(s1); //Image im = vc.CreateImage(s1); //Graphics g = im.getGraphics(); //g.drawImage(im,20,20,this); //g.drawString(s1,20,20); } }
[解决办法]
绝对正确的答案,刚入门学java老师给我们出过的题目...
import java.util.Arrays;
import java.util.Random;
public class Yanzhengma3 {
public static void main(String[] args)
{
char []ary=new char[52];//定义一个数组
count(ary);
System.out.println(Arrays.toString(count(ary)));
System.out.println(Arrays.toString(four(ary)));
}
public static char[] count(char []ary)
{
int j=0;
for(int i=51;i<123;i++)
{
if(((i<57)||(i>=65&&i<90)||(i>=97))&&i!=76&&i!=79&&i!=103&&i!=108&&i!=111)
{
ary[j++]=(char) i;
}
}
return ary;
}
public static char[] four(char[] ary)
{
char[] s =new char[4];
w:for(int i=0;i<4;i++)
{
Random rd=new Random();
int a=rd.nextInt(52);
System.out.print(a+" ");
//System.out.println(ary[a]);
for(int j=0;j<i;j++)
{
if(s[j]==ary[a])
{
i--;
continue w;
}
}
s[i]=ary[a];
//System.out.print(s[j]);
//System.out.println(ary[a]);
}
return s;
}
}
[解决办法]
在达内刚学java时候的回家作业...
[code=Java][/code]
package homework;
import java.util.Arrays;
import java.util.Random;
public class Yanzhengma3 {
public static void main(String[] args)
{
char []ary=new char[52];//定义一个数组
count(ary);
//System.out.println(Arrays.toString(count(ary)));
System.out.println(Arrays.toString(four(ary)));
}
public static char[] count(char []ary)
{
int j=0;
for(int i=51;i<123;i++)
{
if(((i<57)||(i>=65&&i<90)||(i>=97))&&i!=76&&i!=79&&i!=103&&i!=108&&i!=111)
{
ary[j++]=(char) i;
}
}
return ary;
}
public static char[] four(char[] ary)
{
char[] s =new char[4];
w:for(int i=0;i<4;i++)
{
Random rd=new Random();
int a=rd.nextInt(52);
//System.out.print(a+" ");
//System.out.println(ary[a]);
for(int j=0;j<i;j++)
{
if(s[j]==ary[a])
{
i--;
continue w;
}
}
s[i]=ary[a];
//System.out.print(s[j]);
//System.out.println(ary[a]);
}
return s;
}
}
[解决办法]
[code=Java][/code]
package homework;
import java.util.Arrays;
import java.util.Random;
public class Yanzhengma3 {
public static void main(String[] args)
{
char []ary=new char[52];//定义一个数组
count(ary);
//System.out.println(Arrays.toString(count(ary)));
System.out.println(Arrays.toString(four(ary)));
}
public static char[] count(char []ary)
{
int j=0;
for(int i=51;i<123;i++)
{
if(((i<57)||(i>=65&&i<90)||(i>=97))&&i!=76&&i!=79&&i!=103&&i!=108&&i!=111)
{
ary[j++]=(char) i;
}
}
return ary;
}
public static char[] four(char[] ary)
{
char[] s =new char[4];
w:for(int i=0;i<4;i++)
{
Random rd=new Random();
int a=rd.nextInt(52);
//System.out.print(a+" ");
//System.out.println(ary[a]);
for(int j=0;j<i;j++)
{
if(s[j]==ary[a])
{
i--;
continue w;
}
}
s[i]=ary[a];
//System.out.print(s[j]);
//System.out.println(ary[a]);
}
return s;
}
}