js函数返回值问题
用到了jquery 和 php 的一个ajax方法
function imginfo(){ var strtemp="123"; jq(document).ready(function(){ jq.post( 'dt3.php', { a:1 }, function (data) { var str=data.split("|"); for(var i=1; i<=str.length-1;i++){ var temparr=str[i-1].split("@"); if(i<str.length-1) { strtemp += "["+temparr[2]+","+temparr[0]+","+temparr[1]+"]"+","; } else strtemp += "["+temparr[2]+","+temparr[0]+","+temparr[1]+"]"; } } );}); return strtemp;<?phprequire_once './source/class/class_core.php';require_once './source/function/function_home.php';$discuz = & discuz_core::instance();$discuz->init();//print_r($_G);//$str="1,1,1,1,1,1";//DB::query("insert into dz_plugin1 (title,content,datetime,username,uid,filename) values ($str)");$result=DB::query("select * from dz_plugin2");$buff2="";while($rs = mysql_fetch_array($result)){ $buff2.=$rs['title']."@".$rs['url']."@".$rs['filename']."|";}echo $buff2;?>