关于重载歧义的问题
先看代码
// 函数调用void Migrate::process(const DSReferenceID& id,const TapeName& oldtape){ bool ok; Transaction(this,&Migrate::exists,id,oldtape,ok); if(!ok) { Log::info() << oldtape << " does not exist in " << id << endl; return; }}//重载函数//函数1template <class Caller,class Arg1,class Arg2,class Arg3>inline void Transaction(Caller* caller,void (Caller::*proc)(Arg1&,Arg2&,Arg3&),Arg1& arg1,Arg2& arg2,Arg3& arg3){ TransactorM3<Caller,Arg1&,Arg2&,Arg3&>(*caller,proc,arg1,arg2,arg3).update();}//函数2template <class Caller,class Arg1,class Arg2,class Arg3>inline void Transaction(Caller* caller,void (Caller::*proc)(Arg1&,const Arg2&,Arg3&),Arg1& arg1,const Arg2& arg2,Arg3& arg3){ TransactorM3<Caller,Arg1&,const Arg2&,Arg3&>(*caller,proc,arg1,arg2,arg3).update();}//函数3template <class Caller,class Arg1,class Arg2,class Arg3>inline void Transaction(Caller* caller,void (Caller::*proc)(const Arg1&,Arg2&,Arg3&),const Arg1& arg1,Arg2& arg2,Arg3& arg3){ TransactorM3<Caller,const Arg1&,Arg2&,Arg3&>(*caller,proc,arg1,arg2,arg3).update();}//函数4template <class Caller,class Arg1,class Arg2,class Arg3>inline void Transaction(Caller* caller,void (Caller::*proc)(const Arg1&,const Arg2&,Arg3&),const Arg1& arg1,const Arg2& arg2,Arg3& arg3){ TransactorM3<Caller,const Arg1&,const Arg2&,Arg3&>(*caller,proc,arg1,arg2,arg3).update();}