XP下用WINTC写的二分法。该怎么解决

XP下用WINTC写的二分法。
#include"stdio.h"
#include"conio.h"
#define N 5


main()
{
  int array[N];
  int i,number,top,bott,mid,loca,flag=1,sign;
  char c;
  printf("enter data:\12");
  i=0;
  while(i<N)
  {
  scanf("%d",&array[i]);

  if(array[i]<array[i-1]&&i>0)
  {
  printf("enter this data again:\12");
  continue;
  }
  i++;
  }
  printf("\12");
  while(flag)
  {
  printf("input number to look for: ");
  scanf("%d",&number);
  sign=0;
  top=0;
  bott=N-1;
  if((number<array[0])&&(number>array[N-1]))
  {
  loca=-1;

  }
  while(!sign&&top<=bott)
  {
  mid=(top+bott)/2;
  if(number==array[mid])
  {
  loca=mid;
  printf("Has found %d,its position is %d\12",number,loca+1);
  sign=1;
  }
  else if(number<array[mid])
  {
  bott=mid-1;
  }
  else
  {
  top=mid+1;
  }
  }
  if(!sign||(loca==-1))
  {
  printf("can not found %d.\12",number);
  }
  printf("continue or not(Y/N)? \12");
  scanf("%c",&c);
  if(c=='N'||c=='n')
  {
  flag=0;
  }
  }
  getch();
}





这是我在XP下用WINTC写的。。Y/N那块不问我。。直接就跳过了。。。

[解决办法]

C/C++ code

printf("continue or not(Y/N)? \12");      rewind(stdin);   //清空输入缓冲区中留下的回车字符      scanf("%c",&c);