C# dataset！该如何解决

C# dataset！！！！
DataSet result = new DataSet();
string xml=result.GetXml();

以下是xml的值，要怎么能得到各个节点的值
<NewDataSet>
  <Weather>
  <Date>2012年05月02日</Date>
  <Week>星期三(Wed)</Week>
  <Weather>Mostly Sunny</Weather>
  <Tlow>18.3℃</Tlow>
  <Thigh>28.3℃</Thigh>
  </Weather>
  <Weather>
  <Date>2012年05月03日</Date>
  <Week>星期四(Thu)</Week>
  <Weather>Mostly Cloudy</Weather>
  <Tlow>18.9℃</Tlow>
  <Thigh>28.3℃</Thigh>
  </Weather>
</NewDataSet>

[解决办法]
Xmldocument
http://msdn.microsoft.com/zh-cn/library/system.xml.xmldocument.aspx
或者用
Linq to Xml
http://topic.csdn.net/u/20120421/20/7c878b85-9f8f-4bfb-b66a-232d9db421b7.html
[解决办法]

C# code

        /// <summary>        /// 获取指定节点的值        /// </summary>        /// <param name="strFileName">文件路径</param>        /// <param name="nodeName">节点名称</param>        /// <param name="value">设置后的值</param>        /// <param name="nodeDir">指定节点所在的节点目录</param>        /// <returns></returns>        public static string GetNodeValue(string strFileName, string nodeName, string nodeDir)        {            string value = null;            try            {                XmlDocument xmlDoc = new XmlDocument();                xmlDoc.Load(strFileName);                XmlNodeList nodeList = xmlDoc.SelectSingleNode(nodeDir).ChildNodes;//获取bookstore节点的所有子节点                 foreach (XmlNode xn in nodeList)    //遍历所有子节点                 {                    XmlElement xe = (XmlElement)xn;  //将子节点类型转换为XmlElement类型                     if (xe.Name == nodeName)                    {                        value = xe.InnerText.Trim();                        break;                    }                }            }            catch (Exception exp)            {                throw exp;            }            return value;        }        /// <summary>        /// 获取指定节点下面对应属性的值        /// </summary>        /// <param name="strFileName">文件路径</param>        /// <param name="nodeName">节点名称</param>        /// <param name="nodeDir">指定节点所在的节点目录</param>        /// <param name="attribute">节点对应的属性名称</param>        /// <returns></returns>        public static string GetNodeValue(string strFileName, string nodeName, string nodeDir, string attribute)        {            string value = null;            try            {                XmlDocument xmlDoc = new XmlDocument();                xmlDoc.Load(strFileName);                XmlNodeList nodeList = xmlDoc.SelectSingleNode(nodeDir).ChildNodes;//获取bookstore节点的所有子节点                 foreach (XmlNode xn in nodeList)    //遍历所有子节点                 {                    XmlElement xe = (XmlElement)xn;  //将子节点类型转换为XmlElement类型                     if (xe.Name == nodeName)                    {                        //value = xe.InnerText.Trim();                        value = (xe).Attributes[attribute].Value;                        break;                    }                }            }            catch (Exception exp)            {                throw exp;            }            return value;        }
[解决办法]
C# code
 protected void Page_Load(object sender, EventArgs e)        {            string serverpath = Server.MapPath("test1.xml");            Response.Write(GetNodeValue(serverpath, "Weather", "NewDataSet"));        }        public static string GetNodeValue(string strFileName,string nodeName,string nodeDir)        {            string value = null;            try            {                XmlDocument xmlDoc = new XmlDocument();                xmlDoc.Load(strFileName);                XmlNodeList nodeList = xmlDoc.SelectSingleNode(nodeDir).ChildNodes;                int i = 1;                foreach (XmlNode xn in nodeList)                {                    value += i.ToString() + "<br/>";                    XmlElement xe = (XmlElement)xn;                    if (xe.Name == nodeName)                    {                        for (int j = 0; j < 5; j++)                        {                            value += xe.ChildNodes[j].InnerText + "<br/>";                        }                                        }                    i++;                }            }            catch (Exception ex)            {                throw ex;            }            return value;        } 
 
[解决办法]
Dataset ds=new Dataset();
Ds.readxml("文件路径");
之后看你那的ds 中包含几张表

一般情况下 xml中节点的值是一dataset中 Datatable 行列！