关于pivot函数的简单用法
写了个代码一直报错,各位大牛给看下什么原因
SELECT empstatus,64 , 65 FROM (SELECT EmpStatus,compid,badge FROM evw_employee) AS a PIVOT(count(badge) FOR compid IN(64,65)) AS d
SELECT empstatus,[64], [65] FROM (SELECT EmpStatus,compid,badge FROM evw_employee) AS a PIVOT(count(badge) FOR compid IN([64],[65])) AS d