GDI+ 的Matrix:TransformPoints的作用？解决办法

GDI+ 的Matrix::TransformPoints的作用？
这是msdn中的例子：

C/C++ code

VOID Example_TransPoints(HDC hdc){   Graphics graphics(hdc);   Pen pen(Color(255, 0, 0, 255));   Point points[5] = {      Point(50, 100),       Point(100, 50),      Point(150, 125),      Point(200, 100),      Point(250, 150)};   Matrix matrix(1.0f, 0.0f, 0.0f, 2.0f, 0.0f, 0.0f);   graphics.DrawCurve(&pen, points, 5);   matrix.TransformPoints(points, 5);   graphics.DrawCurve(&pen, points, 5); }

C/C++ code

VOID Example_TransPoints(HDC hdc)//以设备上下文句柄为参数{   Graphics graphics(hdc);//实例化绘图对象   Pen pen(Color(255, 0, 0, 255));//定义画笔并着色为蓝   Point points[5] = {  //定义点集      Point(50, 100),       Point(100, 50),      Point(150, 125),      Point(200, 100),      Point(250, 150)};   Matrix matrix(1.0f, 0.0f, 0.0f, 2.0f, 0.0f, 0.0f);//生成仿射变换矩阵   graphics.DrawCurve(&pen, points, 5);//绘制基数样条（就是连接这5个点的平滑曲线）   matrix.TransformPoints(points, 5);//做仿射变换// [1.0  0.0  0.0] [x]   2矩阵相乘，然后得到新的x'=x,y'=2y,这就是将纵坐标乘2就可以了   [2.0  0.0  0.0] [y]      [0.0  0.0  1.0] [1]   graphics.DrawCurve(&pen, points, 5); //再绘制曲线}