一个hash_map的编译问题
新人，不知hash_map的用法，以下这段代码再G++下编译错误，可是看不懂错误说明，求各位指教，谢谢！
#include <cstdio>#include <cstdlib>#include <hash_map>#include <cstring>#include <algorithm>using namespace std;using namespace __gnu_cxx;class Addr{public: char add[6]; Addr() { add[0] = '\0'; } Addr(const Addr& x); inline Addr& operator=(const Addr& x);};Addr::Addr(const Addr& x){ strcpy(add,x.add);}Addr& Addr::operator=(const Addr& x){ strcpy(add,x.add); return *this;}inline bool operator== (const Addr& x,const Addr& y){ if(strcmp(x.add,y.add) == 0) return true; return false;}inline bool operator!= (const Addr& x,const Addr& y){ return !(x == y);}struct str_hash { size_t operator()(const Addr& str) const { size_t __h(0); for(size_t i = 0;i < strlen(str.add);++ i) __h = __h + str.add[i]; return __h; } }; int main(){ Addr b1,b2; int n; char c; scanf("%s %s %d",b1.add,b2.add,&n); hash_map<Addr,Addr> record; for(int i = 0;i < n;++ i) { Addr t1,t2; scanf("%s %c %s",t1.add,&c,t2.add); record.insert(make_pair(t1,t2)); } Addr* w1; Addr* w2; w1 = new Addr[n]; w2 = new Addr[n]; int c1(0),c2(0); w1[c1] = b1; ++ c1; w2[c2] = b2; ++ c2; while(strcmp(b1.add,"-1") != 0) { b1 = record[b1]; w1[c1] = b1; ++ c1; } strcpy(w1[c1].add,"-1"); while(strcmp(b2.add,"-1") != 0) { b2 = record[b2]; w1[c2] = b2; ++ c2; } strcpy(w2[c2].add,"-1"); while(c1 >= 0 && c2 >= 0 && w1[c1] == w2[c2]) { -- c1; -- c2; } ++ c1; printf("%s",w1[c1].add);}