Struts2生成验证码放入session，action无法得到session解决思路

Struts2生成验证码放入session，action无法得到session
在一个RandomAction中生成一个验证码后通过
 ActionContext.getContext().getSession().put("random", rdnu.getString());
将生成的验证码字符串保存到session里，供用户登录或注册时验证是否输入正确
在RandomAction中使用
ActionContext.getContext().getSession().get("random")，可以正常获得session中值
但在另一个LoginAction中，同样的方法，答应出来的确是null;
请问如何解决。
代码如下：
RandomAction.java

Java code

import java.io.ByteArrayInputStream;import Web.RandomNumUtil;import com.opensymphony.xwork2.ActionContext;import com.opensymphony.xwork2.ActionSupport;public class RandomAction extends ActionSupport{       /**     *      */    private static final long serialVersionUID = 1L;    private ByteArrayInputStream inputStream;       public String execute() throws Exception{           RandomNumUtil rdnu=RandomNumUtil.Instance();           this.setInputStream(rdnu.getImage());        ActionContext.getContext().getSession().put("random", rdnu.getString());        System.out.println("生成验证码："+rdnu.getString());        System.out.println("获得验证码："+ActionContext.getContext().getSession().get("random"));        return SUCCESS;       }       public void setInputStream(ByteArrayInputStream inputStream) {           this.inputStream = inputStream;       }       public ByteArrayInputStream getInputStream() {           return inputStream;       }}

RandomNumUtil.java(验证码生成方法类)

Java code

import java.awt.Color;import java.awt.Font;import java.awt.Graphics;import java.awt.image.BufferedImage;import java.io.ByteArrayInputStream;import java.io.ByteArrayOutputStream;import java.util.Random;import javax.imageio.ImageIO;import javax.imageio.stream.ImageOutputStream;public class RandomNumUtil {       privateprovider="java:MSG">

LoginAction.java

Java code

import com.ccniit.service.UserManager; 
 import com.opensymphony.xwork2.ActionContext; 
 import com.opensymphony.xwork2.ActionSupport; 
  
 public class LoginAction extends ActionSupport  { 
  
 /** 
  *  
  */ 
 private static final long serialVersionUID = 1L; 
 /** 
  *  
  */ 
 private String username; 
 private String password1; 
 private String vercode; 
  
 public String getVercode() { 
 return vercode; 
 } 
  
  
  
 public void setVercode(String vercode) { 
 this.vercode = vercode; 
 } 
  
 private String msg; 
  
 public String getMsg() { 
 return msg; 
 } 
  
 public void setMsg(String msg) { 
 this.msg = msg; 
 } 
  
 protected UserManager mgr; 
  
  
 public void setMgr(UserManager mgr) { 
 this.mgr = mgr; 
 } 
  
  
 public String getUsername() { 
 return username; 
 } 
  
 public void setUsername(String username) { 
 this.username = username; 
 } 
  
 public String getPassword1() { 
 return password1; 
 } 
  
 public void setPassword1(String password1) { 
 this.password1 = password1; 
 } 
 public String showReg() throws Exception { 
 return SUCCESS; 
 } 
 public String login() throws Exception { 
 String ver2=(String) ActionContext.getContext().getSession().get("random"); 
 System.out.println("random:" + ver2); 
 System.out.println("用户输入：" + getVercode()); 
 if (getVercode().equals(getVercode())) { 
 if (mgr.login(getUsername(), getPassword1()) > 0) { 
 System.out.println("SUCCESS"); 
 return SUCCESS; 
  
 } else {  
 
  
 setMsg("用户名/密码错误"); 
  
 } 
 } else { 
 setMsg("验证码不匹配,请重新输入"); 
 } 
 System.out.println("INPUT"); 
 return INPUT; 
 } 
  
  
  
 } 
  
 

最后使用spring管理Struts.xml

XML code

<package name="json" extends="json-default">        <action name="validateName" class="validateName">            <result type="json">            </result>        </action>    </package>

applicationContext.xml

XML code

<bean name="rand" class="com.ccniit.Action.RandomAction" scope="prototype" />  

同一个action中可以得到session,但在另一个action中却返回空

[解决办法]

探讨

引用:
没看出什么问题，我有完整的struts2的注册码，要不我发给你吧，给邮箱

kfitdj12333@163.com

查看更多 下一篇