jquery slideUp的callback怎么带参数阿

jquery slideUp的callback如何带参数阿

JScript code

<div id="pa" style="border:#FF0000 1px solid; width:400px; height:700px;">    <div id="top" style="width:100%">        <ul style=" margin:0px; padding:0px; list-style:none;">        <li id="iu">fasdf</li>        <li>fadfasdf</li>        <li>fadfasdf</li>        <li>fadfasdf</li>        </ul>    </div>    </div><script language="javascript">    $("#top ul li").bind('click',function(event){                $('#top').slideUp(1000,function(){此处需要参数的处理，删除li对象});                $('#top').slideDown(1000);    })</script>

HTML code

<script src="http://ajax.Microsoft.com/ajax/jQuery/jquery-1.3.2.min.js" type="text/javascript"> </script> <div id="pa" style="border:#FF0000 1px solid; width:400px; height:700px;">    <div id="top" style="width:100%">        <ul style=" margin:0px; padding:0px; list-style:none;">        <li id="iu">fasdf</li>        <li>fadfasdf</li>        <li>fadfasdf</li>        <li>fadfasdf</li>        </ul>    </div>    </div><script language="javascript">    $("#top ul li").bind('click',function(event){                $('#top').slideUp(1000,(function(obj){            return function(){                alert(obj.html())            }        })($(this)));//        $('#top').slideDown(1000);    })</script>