怎样将这两个查询结果 full jion起来?(当两个查询结果中的 UID和ProjectID都相等时 则进行合并)
第一个查询结果
SELECT UID ,ProjectID, sum([LocalValidCount]) as 本地预约量 ,sum([NoLocalValidCount]) as 外地预约量 FROM DialogueQuantitygroup by UID,ProjectID
select UID,ProjectID, count(1) as 患者总数, sum(case IsNative when 'true' then 1 else 0 end) as '本地患者数量', sum(case IsNative when 'false' then 1 else 0 end) as '外地患者数量', sum(case DiseaseName when '感冒' then 1 else 0 end) as '感冒', sum(case DiseaseName when '发烧' then 1 else 0 end) as '发烧', sum(case DiseaseName when '阑尾炎' then 1 else 0 end) as '阑尾炎'
select * from(SELECT UID ,ProjectID, sum([LocalValidCount]) as 本地预约量 ,sum([NoLocalValidCount]) as 外地预约量 FROM DialogueQuantitygroup by UID,ProjectI) as afull join (select UID,ProjectID, count(1) as 患者总数, sum(case IsNative when 'true' then 1 else 0 end) as '本地患者数量', sum(case IsNative when 'false' then 1 else 0 end) as '外地患者数量', sum(case DiseaseName when '感冒' then 1 else 0 end) as '感冒', sum(case DiseaseName when '发烧' then 1 else 0 end) as '发烧', sum(case DiseaseName when '阑尾炎' then 1 else 0 end) as '阑尾炎') as bon a.UID=b.UID and a.ProjectID=b.ProjectID
[解决办法]
直接写 select * from
(
SELECT UID ,ProjectID,
sum([LocalValidCount]) as 本地预约量
,sum([NoLocalValidCount]) as 外地预约量
FROM DialogueQuantity
group by
UID,ProjectI
) as a
full join
(
select
UID,ProjectID,
count(1) as 患者总数,
sum(case IsNative when 'true' then 1 else 0 end) as '本地患者数量',
sum(case IsNative when 'false' then 1 else 0 end) as '外地患者数量',
sum(case DiseaseName when '感冒' then 1 else 0 end) as '感冒',
sum(case DiseaseName when '发烧' then 1 else 0 end) as '发烧',
sum(case DiseaseName when '阑尾炎' then 1 else 0 end) as '阑尾炎'
) as b
on a.UID=b.UID and a.ProjectID=b.ProjectID
[解决办法]
-- 方法1select * from ([子查询1]) afull join ([子查询2]) b-- 方法2with a as([子查询1]),b as([子查询2])select *from a full join b
[解决办法]
select * from (SELECT UID ,ProjectID, sum([LocalValidCount]) as 本地预约量 ,sum([NoLocalValidCount]) as 外地预约量 FROM DialogueQuantitygroup by UID,ProjectID)a full join (select UID,ProjectID, count(1) as 患者总数, sum(case IsNative when 'true' then 1 else 0 end) as '本地患者数量', sum(case IsNative when 'false' then 1 else 0 end) as '外地患者数量', sum(case DiseaseName when '感冒' then 1 else 0 end) as '感冒', sum(case DiseaseName when '发烧' then 1 else 0 end) as '发烧', sum(case DiseaseName when '阑尾炎' then 1 else 0 end) as '阑尾炎') b on a.UID=b.UID and a.ProjectID and b.ProjectID